How many elements does each of these sets have where a and b are distinct elements? a. ? ({?, ?,{?, ?}}) b. ? ({∅, ?,{?},{{?}}})

Given Class:- import java.util.*; // Iterator, Comparatorpublic class BinarySearchTree<T> implements BSTInterface<T>{protected BSTNode<T> root; // reference to the root of this BSTprotected Comparator<T> comp; // used for all comparisonsprotected boolean found; // used by removepublic BinarySearchTree() // Precondition: T implements Comparable// Creates an empty BST object - uses the natural order of elements.{root = null;comp = new Comparator<T>(){public int compare(T element1, T element2){return ((Comparable)element1).compareTo(element2);}};}public BinarySearchTree(Comparator<T> comp) // Creates an empty BST object - uses Comparator comp for order// of elements.{root = null;this.comp = comp;}public boolean isFull()// Returns false; this link-based BST is never full.{return false;}public boolean isEmpty()// Returns true if this BST is empty; otherwise, returns false.{return (root == null);}public T min()// If this BST is empty, returns null;//…

write down all elements in set notation.

DisjointSet Class    Implementation of this class is done in a1_partc.py A DisjointSet class represents a disjoint set which is a set of sets where every element can only belong to exactly one set. When a DisjointSet class is instantiated it is passed nothing and contains no sets. It make an empty Python dictionary which will be used to store the elements of the DisjointSet. The DisjointSet has the following member functions: def make_set(self,element) If element already exists within the Disjoint set, the function does nothing and returns false. If element does not exist in the DisjointSet, this function will add it to the DisjointSet by: make a new SetList object containing only one node, with the element as only value in the SetList adding a new dictionary entry where element is the key and a reference to the node containing element as the value return true Suppose we ran the following code:     ds = DisjointSet()    ds.make_set("cat")    ds.make_set("dog")    ds.make_set("fish")…