MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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Question
How is the distance from the sun for planets in our solar system related to the mean temperature of each planet? To find out, a
Based on the scatterplot and computer output, a reasonable estimate of mean temperature in Kelvin for Saturn, which is 886.7 million miles away from the sun is:
4.822 degrees Kelvin because ŷ = −0.4536(In 886.7) + 7.9009 = 4.822.
124.2 degrees Kelvin because and e4.822 = 124.2.
709.0 degrees Kelvin because and e6.564 = 709.0.
0.05 degrees Kelvin because and e−3.008 = 0.0494.
Transcribed Image Text:In(Temperature) vs. In(Distance)
O 124.2 degrees Kelvin because
6.8
6.6
6.4
6.2
In y = - 0.4536(In 886.7) + 7.9009 =4.822 and e4.822 = 124.2.
709.0 degrees Kelvin because
6
5.8
5.6
5.4
5.2
In y = - 0.4536(log 886.7) + 7.9009 =6.564 and e6.564 = 709.0.
O 0.05 degrees Kelvin because
In y = - 0.4536(In 886.7) + 0.0706 = – 3.008 and e-3.008 =
4.8
4.6
4.4
4.2
0.0494.
4
5 6
7
8
9
In(Distance)
SE Coef
0.4381
0.0706
Predictor
Coef
T
P
Constant
7.9009
18.03
0.000
In Distance
-0.4536
-6.42
0.004
S = 0.3446
R-Sq = 85.5
R-Sq (adj) = 83.2%
8642 Ooo4 250o 424
5555
444
In(Temperature)
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