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Hexane (1)/ ethanol (2) / methylcyclopentane (3)/ benzene (4) system Determine the following: 1. Y₁₁₁, P at T = 343.15 K COMPONENT x1 1 0.25 2 0.40 3 0.20 4 0.15 2. Y₁₁₁T at P = 1.01325 COMPONENT Ул 1 0.25 2 0.40 3 0.20 4 0.15

Hexane (1)/ ethanol (2) / methylcyclopentane (3)/ benzene (4) system Determine the following: 1. Y₁₁₁, P at T = 343.15 K COMPONENT x1 1 0.25 2 0.40 3 0.20 4 0.15 2. Y₁₁₁T at P = 1.01325 COMPONENT Ул 1 0.25 2 0.40 3 0.20 4 0.15

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Hexane (1) / ethanol (2) / methylcyclopentane (3)/ benzene (4) system Determine the following: 1. ₁,₁,₁,P at T = COMPONENT 1 2 3 4 COMPONENT 1 2 = 343.15 K 3 4 x1 0.25 0.40 2. ₁,₁,₁,T at P = 1.01325 1 0.20 0.15 У1 0.25 0.40 0.20 0.15
Transcribed Image Text:Hexane (1) / ethanol (2) / methylcyclopentane (3)/ benzene (4) system Determine the following: 1. ₁,₁,₁,P at T = COMPONENT 1 2 3 4 COMPONENT 1 2 = 343.15 K 3 4 x1 0.25 0.40 2. ₁,₁,₁,T at P = 1.01325 1 0.20 0.15 У1 0.25 0.40 0.20 0.15
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