Given the thermochemical equations x2 +32 2xYAH = -340kJ -> -> ΔΗ *2+2Z2 - 2xZ2,AH2 = -180kJ 2Y2 + Z2 -2Y, Z, AH, H = -250kJ 2 Calculate the change in enthalpy for the reaction. 3 4xY₂ +7Z +7Z2 -> 6Y2Z+4x2 AH =

Chemistry: Matter and Change
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ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
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Chapter15: Energy And Chemical Change
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Problem 71A
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Given the thermochemical equations
x2 +32 2xYAH = -340kJ
->
->
ΔΗ
*2+2Z2 - 2xZ2,AH2 = -180kJ
2Y2 + Z2
-2Y, Z, AH,
H = -250kJ
2
Calculate the change in enthalpy for the
reaction.
3
4xY₂ +7Z
+7Z2
->
6Y2Z+4x2
AH =
Transcribed Image Text:Given the thermochemical equations x2 +32 2xYAH = -340kJ -> -> ΔΗ *2+2Z2 - 2xZ2,AH2 = -180kJ 2Y2 + Z2 -2Y, Z, AH, H = -250kJ 2 Calculate the change in enthalpy for the reaction. 3 4xY₂ +7Z +7Z2 -> 6Y2Z+4x2 AH =
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