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Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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A
Question 52
Given the following reaction:
MnO4 (aq) + H₂C₂O4(aq) → Mn2+ (aq) + CO₂(g)
Which element is being reduced?
00
ΟΗ
O Mn
OC
Question 53
Given the following reaction:
2 H₂O
2 H2 (g) + O₂ (g)
Calculate the mass in grams of water needed to produce 964 mL of oxygen
atm.
Procte"
Transcribed Image Text:D
A
Question 52
Given the following reaction:
MnO4 (aq) + H₂C₂O4(aq) → Mn2+ (aq) + CO₂(g)
Which element is being reduced?
00
ΟΗ
O Mn
OC
Question 53
Given the following reaction:
2 H₂O
2 H2 (g) + O₂ (g)
Calculate the mass in grams of water needed to produce 964 mL of oxygen
atm.
Procte
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- For each of the following reactions, assign oxidation numbers to each atom/ion and indicate whether the equation represents a redox reaction. If it does, identify the oxidation and reduction components. a) Cu (s) + 2 AgNO3 (aq) → 2 Ag (s) + Cu(NO3)2 (aq) b) 2 NaCl (l) → 2 Na (l) + Cl2 (g) c) 2 C4H10 (g) + 13 O2 (g) → 8 CO2 (g) + 10 H2O (l) d) 2 H2O2 (l) → 2 H2O (l) + O2 (g)arrow_forwardOne way in which the useful metal copper is produced is by dissolving the mineral azurite, which contains copper(II) carbonate, in concentrated sulfuric acid. The sulfuric acid reacts with the copper(II) carbonate to produce a blue solution of copper(II) sulfate. Scrap iron is then added to this solution, and pure copper metal precipitates out because of the following chemical reaction: Fe (s) + CuSO4 (aq) → Cu (s) + FeSO4 (aq)Suppose an industrial quality-control chemist analyzes a sample from a copper processing plant in the following way. He adds powdered iron to a 300.mL copper(II) sulfate sample from the plant until no more copper will precipitate. He then washes, dries, and weighs the precipitate, and finds that it has a mass of 67.mg . Calculate the original concentration of copper(II) sulfate in the sample. Be sure your answer has the correct number of significant digits.arrow_forwardWhen the following molecular equation is balanced using the smallest possible integer coefficients, the values of these coefficients are: HgO (s) →→→ Hg (1) + 0₂ (g)arrow_forward
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