Given the following linked list where each node has a data I link field & uses he painters plipz,p3,P Draw a Simikr diagiam to show how this ponfiguration ghanges when the givey spgment of Code epecuts. (Assume each part is independent from Hle other, a p3=P2; p4 link= p2.links execeutes, b) p3.link=p2.link; p2.link pr. link; py. link = p3. link; p4. a parlink= p3; pi. link.linkpl; pi. link. link=pa.link; p4=noll; pa= p4;

New Perspectives on HTML5, CSS3, and JavaScript
6th Edition
ISBN:9781305503922
Author:Patrick M. Carey
Publisher:Patrick M. Carey
Chapter12: Working With Document Nodes And Style Sheets: Creating A Dynamic Document Outline
Section12.1: Visual Overview: Exploring The Node Tree
Problem 5QC
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1.Assume some Node class with info link fields . Complete this method in class List that returns a reference to the node containing the data item in the argument findThis, Assume that findThis is in the list 

 

public class list 

{

protected Node head ;

Protected int size ;

Public Node find (char find this)

    {

    Node curr = head;   

    while(curr != null)

      {

        if(curr.info == findThis) 

           return curr;

        curr = curr.link;

      }

        return -1;                          

    }

}

Given the following linked list where each node
has a data & link field & uses tle panters plsp3p3P
J.
Draw a simi ar diagam to show how this ponfiquration
changes when the given segment of Code ekecuts,
(Assume each part'is indepentent from the ofher,
a)
pp2;
3=
p4.link=p2.links
b) p3.link=p2.link;
Pa.link = pi. link:
= pl.
py. link = p3. links
p4.
O parlink= p3;
pi. link.linkpl;
pi, link,link=pa.link;
p4=null;
pa= p4;
Transcribed Image Text:Given the following linked list where each node has a data & link field & uses tle panters plsp3p3P J. Draw a simi ar diagam to show how this ponfiquration changes when the given segment of Code ekecuts, (Assume each part'is indepentent from the ofher, a) pp2; 3= p4.link=p2.links b) p3.link=p2.link; Pa.link = pi. link: = pl. py. link = p3. links p4. O parlink= p3; pi. link.linkpl; pi, link,link=pa.link; p4=null; pa= p4;
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