Given the following C code: atruct Node int data: struct Node prev struct Node nexts Which of the following statements deletes the node pointed by X? Assume that X points to the first node of linked list and head points to the head of linked list. a) X->prev-Xx->next; X->next-X->prev; b) Head-X->next; Head >prev-NULL; c) Head-X->prev: X->next-NULL; d) X->prev->prev - X->prev; X->next->next-X->next;

T/F: All Linked Lists must have head node.

Please fill in the blanks from 26 to 78 in C. /*This program will print students’ information and remove students using linked list*/ #include<stdio.h> #include<stdlib.h> //Declare a struct student (node) with 5 members //each student node contains an ID, an age, graduation year, // 1 pointer points to the next student, and 1 pointer points to the previous student. struct student { int ID; int age; int classOf; struct student* next; struct student* prev; }; /* - This function takes the head pointer and iterates through the list to get all 3 integers needed from the user, and save it to our list - Update the pointer to point to the next node.*/ void scanLL(struct student* head) { while(head != NULL) //this condition makes sure the list is not at the end { printf("Lets fill in the information. Enter 3 integers for the student's ID, age, and graduation year: "); scanf("%i %i %i",&&head->ID, &head->age, &head->classOf); //in order: ID, age, graduation…

lst1= [4,3,2,6,2] and lst2=[1,2,4] then the new_list is [2,2,4]. Assign the new-list to variable new_list and sort. Code: What is wrong with this code? lst1= [4,3,2,6,2]  lst2=[1,2,4] new_list=[] for elements1 in lst1:    for elements2 in lst2:        elements1==elements2:        new_list.append(elements1)       new_list.sort()

Use the following node definition for this problem.struct NodeInt32{int32_t value; NodeInt32* next;} Write a function which searches a non-empty linked list for a target value. Its exact signature should be: NodeInt32* find(NodeInt32* head, int32_t target); The function should return the first node whose value equals target. If the target is not found in the list, then the function should return NULL.

please complate code in  fill in the blanks

In this code: #include <iostream> #include <string> using namespace std;// Node struct to store data for each song in the playliststruct Node { string data; Node * next;};// Function to create a new node and return its addressNode * getNewNode(string song) { Node * newNode = new Node(); newNode -> data = song; newNode -> next = NULL; return newNode;}// Function to insert a new node at the head of the linked listvoid insertAtHead(Node ** head, string song) { Node * newNode = getNewNode(song); if ( * head == NULL) {  * head = newNode;  return;} newNode -> next = * head; * head = newNode;}// Function to insert a new node at the tail of the linked listvoid insertAtTail(Node ** head, string song) { Node * newNode = getNewNode(song); if ( * head == NULL) {  * head = newNode;  return; } Node * temp = * head; while (temp -> next != NULL) {  temp = temp -> next; } temp -> next = newNode;}// Function to remove a node from the linked listvoid removeNode(Node ** head,…

Project 2: Singly-Linked List The purpose of this assignment is to assess your ability to: ▪Implement sequential search algorithms for linked list structures ▪Implement sequential abstract data types using linked data ▪Analyze and compare algorithms for efficiency using Big-O notation For this assignment, you will implement a singly-linked node class. Use your singly-linked node to implement a singly-linked list class that maintains its elements in ascending order. The SinglyLinkedList class is defined by the following data: ▪A node pointer to the front and the tail of the list Implement the following methods in your class: ▪A default constructor list<T> myList ▪A copy constructor list<T> myList(aList) ▪Access to first elementmyList.front() ▪Access to last elementmyList.back() ▪Insert value myList.insert(val) ▪Remove value at frontmyList.pop_front() ▪Remove value at tailmyList.pop_back() ▪Determine if emptymyList.empty() ▪Return # of elementsmyList.size() ▪Reverse order of…

@6 The Reference-based Linked Lists: Select all of the following statements that are true.   options:   As a singly linked list's node references both its predecessor and its successor, it is easily possible to traverse such a list in both directions.   According to the terminology introduced in class, the head reference variable in a singly linked list object references the list's first node.   According to the terminology introduced in class, in a doubly linked list, each node references both the head and tail node.   In a double-ended singly linked list, the tail reference variable provides access to the entire list.   In a circular linked list, the last node references the first node.

program Linked List: modify the following program to make a node containing data values of int, char, and string. #include <iostream> using namespace std; struct node { int data; struct Node *next; }; struct Node* head = nullptr;//or Null or 0; void insert(int new_data) { struct Node* new_node=(struct Node*) new(struct Node); new_mode->data=new_data; new_mode->next=head; head=new_node; } void display() { struct Node* ptr; ptr=head; while(ptr ! = NULL) {   cout<<ptr->data<<""; ptr=ptr->next; } } int main() { insert{2}; display{}; return0; }