fx(x)=e, x≥0. We observe X in the presence of noise N: Y = X + N. The noise is randomly drawn from the uniform distribution over the interval [-1/2, 1/2]; that is, given X = x, the conditional pdf of Y is uniform on [x- 1/2, x + 1/2]. (a) Find the pdf fy (y) of Y. (b) Suppose we observe Y = 1/2. What is the conditional pdf fx(x|Y = 1/2)? Given this observation, what is the most likely value for X? (In other words, where does fx(x|Y 1/2) take its maximum value?)

Introductory Circuit Analysis (13th Edition)
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Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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In the image, a continuous random variable x has the following pdf:

fx(x)=e, x≥0.
We observe X in the presence of noise N:
Y = X + N.
The noise is randomly drawn from the uniform distribution over the interval [-1/2, 1/2]; that
is, given X = x, the conditional pdf of Y is uniform on [x- 1/2, x + 1/2].
(a) Find the pdf fy (y) of Y.
(b) Suppose we observe Y = 1/2. What is the conditional pdf fx(x|Y = 1/2)? Given
this observation, what is the most likely value for X? (In other words, where does
fx(x|Y 1/2) take its maximum value?)
Transcribed Image Text:fx(x)=e, x≥0. We observe X in the presence of noise N: Y = X + N. The noise is randomly drawn from the uniform distribution over the interval [-1/2, 1/2]; that is, given X = x, the conditional pdf of Y is uniform on [x- 1/2, x + 1/2]. (a) Find the pdf fy (y) of Y. (b) Suppose we observe Y = 1/2. What is the conditional pdf fx(x|Y = 1/2)? Given this observation, what is the most likely value for X? (In other words, where does fx(x|Y 1/2) take its maximum value?)
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