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Further the last question, if the lady passed point A and the drag resistance force on bicycle has no change but she can't maintain the constant speed any more, O determine the acceleration of the bicycle if 02 = 9 (Hints, you may need to use the drag resistance force from the previous question).

Further the last question, if the lady passed point A and the drag resistance force on bicycle has no change but she can't maintain the constant speed any more, O determine the acceleration of the bicycle if 02 = 9 (Hints, you may need to use the drag resistance force from the previous question).

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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A lady on a bicycle is going down a hill. If the initial slope angle θ1 = 5 and she has a constant speed with no braking or pedaling, determine the drag force asserted on bicycle tires by the ground (Assume the total mass for her and the bicycle is 70 kg and neglect air resistance). Question 2 options: F=35.93 N F=0.0483g N F=59.85 N F=0.0523mg N Note:- • Do not provide handwritten solution. Maintain accuracy and quality in your answer. Take care of plagiarism. • Answer completely. • You will get up vote for sure.
Further the last question, if the lady passed point A and the drag resistance force on bicycle has no change but she can't maintain the constant speed any more, = determine the acceleration of the bicycle if 2 9 (Hints, you may need to use the drag resistance force from the previous question). v constant A 02 ax=0.5131 m/s² a = 1.8921 m/s² ax = 2.3896 m/s² ax=0.3413 m/s²
Transcribed Image Text:Further the last question, if the lady passed point A and the drag resistance force on bicycle has no change but she can't maintain the constant speed any more, = determine the acceleration of the bicycle if 2 9 (Hints, you may need to use the drag resistance force from the previous question). v constant A 02 ax=0.5131 m/s² a = 1.8921 m/s² ax = 2.3896 m/s² ax=0.3413 m/s²
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