From your Lineweaver-Burk plot,the vlaues are: Km Vmax Uninhibited 0.09 mmol/L 3.02 min/mmol Inhibited 6.22 mmol/L 9.98 min/mmol By describing the potential changes in the kinetic parameters, identify and justify the type of inhibitor that was inhibiting the acid phosphatase activity.
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From your Lineweaver-Burk plot,the vlaues are:
|
Km |
Vmax |
Uninhibited |
0.09 mmol/L |
3.02 min/mmol |
Inhibited |
6.22 mmol/L |
9.98 min/mmol |
By describing the potential changes in the kinetic parameters, identify and justify the type of inhibitor that was inhibiting the acid phosphatase activity.
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- 13. 0.9% (m/v) NaCI solution and 5% (m/v) glucose solution are both isotonic to red blood cells. SHOW your work and watch sig figs & units. c. convert the concentration from M to % (m/v) for a 0.342 M NaC solution. (HINT: convert to g/ml and then multiple by 100%)uizzes/67365/take Based on the image below, select the correct statements. Note: There may be more than 1 correct response. I Ribose 5-phosphate ribose phosphate pyrophosphokinase (PRPP synthetase) glutamine-PRPP amidotransferase adenylosuccinate synthetase AMP > 5-Phosphoribosylamine I adenylosuccinate PRPP lyase 9 steps Adenylosuccinate AMP IMP <-- ADP - AMP <-- GMP <-- IMP IMP dehydrogenase <- GMP - XMP ADP ATP GMP يمد XMP-glutamine amidotransferase Increased levels of ADP inhibit the production of PRPP. Increased levels of GMP inhibit the production of XMP. O Increased ADP activates PRPP synthase to increase PRPP levels. Increased IMP activates glutamine-PRPP amidotransferase to further increase IMP levels. 8 OBCThe equilibrium constant for the hydrolysis of the peptide alanylglycine (Gly-Ala in the reaction from Part B) by a peptidase is K = 9.0 × 10² at 310 K. Calculate AG for this reaction. Express the Gibbs free energy to three significant figures. AG = Submit ΠΑΠΙ ΑΣΦ Request Answer ? kJ/mol Keq [Gly] [Ala] [Gly-Ala]
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- Intracellular concentrations in resting muscle are as follows: fructose- 6-phosphate, 1.0 mM; fructose-1,6-bisphosphate, 10 mM; AMP, 0.1 mM; ADP, 0.5 mM; ATP, 5 mM; and P, 10 mM. Is the phosphofructokinase reac- tion in muscle more or less exergonic than under standard conditions? By how much?Intramitochondrial ATP concentrations are about 5 mM, and phos- phate concentration is about 10 mM. If ADP is five times more abundant than AMP, calculate the molar concentrations of ADP and AMP at an energy charge of 0.85. Calculate AG for ATP hydrolysis at 37 °C under these conditions. The energy charge is the concentra- tion of ATP plus half the concentration of ADP divided by the total adenine nucleotide concentration: [ATP] + 1/2[ADP] [ATP] + [ADP] + [AMP]The isomerization of dihydroxyacetone phosphate (DHAP) to glyceraldehyde 3-phosphate (GAP) is catalyzed by triose phosphate isomerase. In the cell, the concentration ratio of DHAP/GAP = 5.5. Calculate [DHAP] (in M) when [GAP] = 0.00002