From two dictionary objects created in the codes below, find letters that only exist in one of the dictionaries. Use a SET object(s) and its mathematical operator(s).       import string # import string library import random # import random library   # a_base is a string containing concatenation of letters s_base = string.ascii_letters   # random.seed() accepts any integer to initialize random numbers random.seed(582)   # s is a string variable s = ""   # this line creates a loop starting from 0 to 199 for i in range(200):  # this line randomly selects letters from s_base variable and concatenates them to the value stored in s  s += s_base[random.randint(0, 25)] # this line prints the value of s print(s)   # count each char frequency count = {} for ch in s:   if ch in count:     count[ch] = count[ch]+1   else:     count[ch] = 1   # print the frequency for key in count:   print("{} -> {}".format(key, count[key]))       def char_frequency(s):   dict = {}   for d in s:     keys = dict.keys()     if d in keys:       dict[d] += 1     else:       dict[d] = 1   return dict     counts = char_frequency(s) print(char_frequency(s))     Subject: Python Programming

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Author:James Kurose, Keith Ross
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From two dictionary objects created in the codes below, find letters that only exist in one of the dictionaries. Use a SET object(s) and its mathematical operator(s).

 

 

 

import string # import string library

import random # import random library

 

# a_base is a string containing concatenation of letters

s_base = string.ascii_letters

 

# random.seed() accepts any integer to initialize random numbers

random.seed(582)

 

# s is a string variable

s = ""

 

# this line creates a loop starting from 0 to 199

for i in range(200):

 # this line randomly selects letters from s_base variable and concatenates them to the value stored in s

 s += s_base[random.randint(0, 25)]

# this line prints the value of s

print(s)

 

# count each char frequency

count = {}

for ch in s:

  if ch in count:

    count[ch] = count[ch]+1

  else:

    count[ch] = 1

 

# print the frequency

for key in count:

  print("{} -> {}".format(key, count[key]))

 

 

 

def char_frequency(s):

  dict = {}

  for d in s:

    keys = dict.keys()

    if d in keys:

      dict[d] += 1

    else:

      dict[d] = 1

  return dict

 

 

counts = char_frequency(s)

print(char_frequency(s))

 

 

Subject: Python Programming

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