Four charges of equal magnitude q = 1.88 µC are situated as shown in the diagram below. If d = 0.98 m, find the electric potential at location A due to the four charges in Volts

The work done by an external force to move a charge from point A to point B is 15x10^47. If the charge was started from rest and had a kinetic energy 4.82x10 KJ when it reached point B. What must be the potential difference between A and B? How far apart is point B from point A?

Four charges of equal magnitude q = 1.95 µC are situated as shown in the diagram below. If d = 0.91 m, find the electric potential at location A due to the four charges. V -9 d d A 2d 9 9 d -9

Vtot =0 O Symmetric Cross = 200 C, and the vertical rod has a charge of -Q = -200 C. The charges on both Two rods of equal length L = : 1.69 m form a symmetric cross. The horizontal rod has a charge of Q rods are distributed uniformly along their length. Calculate the potential at the point P at a distance D = 2.28 m from one end of the horizontal rod. Special note: You're going to have to take the difference between the potentials made by the positive and negative rods, which are similar numbers. That means that to get an accurate answer you need to keep more digits than usual while you're doing your calculation. + + + + + + + + + + + + L P ·D -

A uniform electric field of magnitude 295 V/m is directed in the negative y direction as shown in the figure below. The coordinates of point  are  (−0.300, −0.750) m,  and those of point  are  (0.750, 0.450) m.  Calculate the electric potential difference VB − VA using the dashed-line path.

What will be the electric potential at a distance of 2.5 m from a point charge of 7.5 uC? Group of answer choices 2.7 x 10^4 V 7.9 x 10^4 V 3.8 x 10^4 V 5.2 x 10^4 V

Two rods of equal length L=1.69 m form a symmetric cross. The horizontal rod has a charge of Q=200 C, and the vertical rod has a charge of −Q=−200 C. The charges on both rods are distributed uniformly along their length. Calculate the potential at the point P at a distance D=2.28 m from one end of the horizontal rod. Special note: You're going to have to take the difference between the potentials made by the positive and negative rods, which are similar numbers. That means that to get an accurate answer you need to keep more digits than usual while you're doing your calculation.

An electron moving parallel to the x-axis has an initial speed of 3.70 x 106 m/s at the origin. Its speed is reduced to 1.40 x 105 m/s at the point x = 2.00 cm. Calculate the potential difference between the origin and that point. Which point is at the higher potential?

The drawing shows a set of equipotential surfaces seen in cross-sections. Each is labeled according to its electric potential. A 2.4 x 10-7 C point charge is placed at position A. Find the work done on the point charge by the electric force when it is moved (a) from A to B, and (b) A to C. B +650.0 V +550.0 V D +150.0 V +450.0 V +250.0 V 2.0 cm +350.0 V