Vtot =0 O Symmetric Cross = 200 C, and the vertical rod has a charge of -Q = -200 C. The charges on both Two rods of equal length L = : 1.69 m form a symmetric cross. The horizontal rod has a charge of Q rods are distributed uniformly along their length. Calculate the potential at the point P at a distance D = 2.28 m from one end of the horizontal rod. Special note: You're going to have to take the difference between the potentials made by the positive and negative rods, which are similar numbers. That means that to get an accurate answer you need to keep more digits than usual while you're doing your calculation. + + + + + + + + + + + + L P ·D -

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Vtot =0
O
Symmetric Cross
=
200 C, and the vertical rod has a charge of -Q = -200 C. The charges on both
Two rods of equal length L = : 1.69 m form a symmetric cross. The horizontal rod has a charge of Q
rods are distributed uniformly along their length. Calculate the potential at the point P at a distance D = 2.28 m from one end of the horizontal rod. Special note: You're going to have to
take the difference between the potentials made by the positive and negative rods, which are similar numbers. That means that to get an accurate answer you need to keep more digits
than usual while you're doing your calculation.
+ + + + + +
+ + + + + +
L
P
·D -
Transcribed Image Text:Vtot =0 O Symmetric Cross = 200 C, and the vertical rod has a charge of -Q = -200 C. The charges on both Two rods of equal length L = : 1.69 m form a symmetric cross. The horizontal rod has a charge of Q rods are distributed uniformly along their length. Calculate the potential at the point P at a distance D = 2.28 m from one end of the horizontal rod. Special note: You're going to have to take the difference between the potentials made by the positive and negative rods, which are similar numbers. That means that to get an accurate answer you need to keep more digits than usual while you're doing your calculation. + + + + + + + + + + + + L P ·D -
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