Positive charge Q is distributed uniformly along the x axis from x = -a/2 to x = +a/2. Point P is on the x axis at x = r where r > a/2. The diagram shows a segment of the line of charge at a distance x from the origin. The X. а 0 dx length of this segment is dx and its charge is dQ. 2 (a) Show that the contribution to the electric potential at P due to the element of charge dQ is 1 Q dx dV 4n€, a r – x' You may add to the diagram above if that is helpful. (b) Calculate V at P due to the entire line of charge. Appendix B of your text contains useful integrals. (c) Find an approximate expression for V if r » a and explain why your result seems reasonable. 8 IN

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Positive charge Q is distributed
uniformly along the x axis from
x = -a/2 to x = +a/2. Point P
is on the x axis at x = r where
r > a/2. The diagram shows a
segment of the line of charge at a
distance x from the origin. The
length of this segment is dx and
its charge is dQ.
а
а
2
0 dx
2
(a) Show that the contribution to the electric potential at P due to the element of charge dQ is
1 Q dx
dV
4TE, ar – x
You may add to the diagram above if that is helpful.
(b) Calculate V at P due to the entire line of charge. Appendix B of your text contains useful integrals.
(c) Find an approximate expression for V if r » a and explain why your result seems reasonable.
Transcribed Image Text:Positive charge Q is distributed uniformly along the x axis from x = -a/2 to x = +a/2. Point P is on the x axis at x = r where r > a/2. The diagram shows a segment of the line of charge at a distance x from the origin. The length of this segment is dx and its charge is dQ. а а 2 0 dx 2 (a) Show that the contribution to the electric potential at P due to the element of charge dQ is 1 Q dx dV 4TE, ar – x You may add to the diagram above if that is helpful. (b) Calculate V at P due to the entire line of charge. Appendix B of your text contains useful integrals. (c) Find an approximate expression for V if r » a and explain why your result seems reasonable.
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