For the reaction2C2H6(g) + 7O2(g)4CO2(g) + 6H2O(g)H° = -2.86×103 kJ and S° = 92.7 J/KAt standard conditions, this reaction would be product favored at relatively low temperatures. at all temperatures. at relatively high temperatures. at no temperature.

For the reaction Fe,03(s) + 2Al(s) Al,O3(8) + 2Fe(s) AH° - -851.5 kJ and AS° = -37.0 J/K %3D The maximum amount of work that could be done when 2.36 moles of Fe,03(s) react at 338 K, 1 atm is kJ. Assume that AH° and AS° are independent of temperature.

For the reaction 2NH3(g) + 202(g)→N20(g) + 3H20(1) AH° = -683 kJ and AS° = -366 J/K !! AG would be less than zero at temperatures (above, below) К. Enter above or below in the first box and enter the temperature in the second box. Assume that AH° and AS° are constant.

Given the data in the table in the figure at 1 atm and 25.0 °C, calculate the standard heat of reaction, ∆H°₂₅, for the reaction Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s)   A) 216.8 kJ are evolved per mole B) 88.0 kJ are evolved per mole C) 88.0 kJ are absorbed per mole D) 216.8 kJ are absorbed per mole

A mole of sodium met is added to water How much work is done on the atmosphere by the subsequent reaction if the temperature is 25 C°

For the reaction 3Fe₂O3(s) + H₂(g)- →2Fe3O4(s) + H₂O(g) AH° = -6.00 kJ and AS° = 88.7 J/K At standard conditions, this reaction would be product favored O O O O relatively high temperatures. at no temperature. at at all temperatures. at relatively low temperatures.

Hìnt: No calculations are required. For the reaction 2C02(g) + 5H2(g)→C2H2(g) + 4H20(g) AH° = 46.5 k) and AS° = -125 J/K %3D At standard conditions, this reaction would be product favored at relatively low temperatures. at relatively high temperatures. at no temperature. O at all temperatures.

Hint: No calculations are required. For the reaction 2H₂O(1) 2H₂(g) + O₂(g) AH° 572 kJ and AS° = 327 J/K At standard conditions, this reaction would be product favored O at all temperatures. at no temperature. O at relatively low temperatures. O at relatively high temperatures.

Use the given standard enthalpies of formation to calculate AH° for the following reaction (SHOW CALCULATIONS) 2 Fe304(s) + C02(g) → 3 Fe2O3(s) + CO(g) Species AH°†, kJ/mol Fe2O3 (s) -824.2 FezO4 (s) -1118.4 CO (g) CO2 (8) -110.5 -393.5

O-234 kJ 234 kJ -150. kJ -117 kJ Given: -1835kJ AH°, AHᵒf (kJ/mol) -941 -840 QUESTION 12 Use the standard reaction enthalpies given below to determine AH°rxn for the following reaction: P4(g) + 10 Cl₂(g) → 4 PC|5(s) PC15(s) → PC13(g) + Cl₂(g) P4(g) + 6 Cl₂(g) → 4 PCl3(g) rxn IF7(g) IF 5(9) 2(g) 62.42 = ? ΔΗ° rxn AH°rxn = +157 kJ = -1207 KJ QUESTION 13 Use the AH°f and AH°rxn information provided to calculate AH°f for IF: IF7(9) + 12(g) → IF5(g) + 2 IF(g) AH°rxn = -89 kJ