Use the given standard enthalpies of formation to calculate AH° for the following reaction (SHOW CALCULATIONS) 2 Fe304(s) + CO2(g) → 3 Fe203(s) + CO(g) Species AH°f, kJ/mol Fe2O3 (s) -824.2 FezO4 (s) -1118.4 CO (g) CO2 (g) -110.5 -393.5

2. Calculating enthalpy: AH = -206 kJ mol¹¹, 3 Fe(s) + 2 O₂(g) → Fe3O4 (S) AH = -136 kJ mol-¹, a) Given 2Fe(s) + 1.5 O₂(g) → Fe₂O3 (S) determine AH, for the following reaction: 4Fe₂O3(s) + Fe(s) → 3Fe3O4 (s) Is this reaction exothermic or endothermic? Is this enough information to inform whether this reaction occurs or not? O b) Given AH vap of water at 373 K = 40.7 kJ mol¹¹, C₂(l)=75.2 J mol¹¹K²¹ and ₂(g)=33.6 J mol¹¹K²¹, calculate AHvap of water at 298 K.

Given the following two reactions:(1)Fe(s) + Cl2(g)->FeCl2(s) H(1) = -341.8 kJ(2)Hg(l) + Cl2(g)->HgCl2(s) H(2) = -224.3 kJcalculate the enthalpy change for the following reaction:(3) FeCl2(s) + Hg(l)-> Fe(s) + HgCl2(s) H(3) = kJ

A scientist measures the standard enthalpy change for the following reaction to be 184.8 kJ:Fe3O4(s) + 4 H2(g) 3Fe(s) + 4 H2O(g)Based on this value and the standard enthalpies of formation for the other substances, the standard enthalpy of formation of Fe3O4(s) is kJ/mol.

Substance SiO,(s) SICLO H,O) HCIE) AH°, (kJ/mol) -910.7 -687.0 -285.83 -92.307 Calculate the standard enthalpy change for the following reaction: SICI4(1) + 2H20(1) → SIO2 (s) + 4HCI (g)

Hydrobromic acid (HBr) is a commonly used acid for adding bromine to organic compounds. As bromine makes for an easily replaceable substituent, these bromine precursors are a necessary part of a vast amount of organic eynthesis, Calculate the reaction enthalpy for the synthesis of HBr according to H2(g) + Bra)2Br(g) Use the following information: NH3(g) +HBr(g) → NHABr(s) AH =-188.32 kJ Na(g) + 3H2(g) → 2NH3(g) AH = -92.22 kJ N2(g) + 4H2(g) + Br2(1) → 2NHABr(s) AH =-541.66 kJ a. AH =-728 kmol b. AH =-1010.52 KJjmol C. AH =-826.08 KJ/mol d. AH =728 kJ/mol e. AH = -257.24 kJ/mol Clear my choice

use the standard reaction enthalpies given below to determine ▲H°rxn for the following reaction (see image)

20) The standard enthalpy change for the reaction below is -196.0 kJ. Use Table below to calculate the standard enthalpy of formation of H₂O (1). 2H₂O2 (1) ->>> 2H₂O (1) + O₂ (g) Substance H₂O2 (1) AH° (kj/mole) -187.8

Use the molar bond enthalpy data in the table to estimate the value of AHin for the equation. rxn NH3(g) + 2O₂(g) → HNO3(g) + H₂O(g) The bonding in the molecules is shown. H AHixn = H O اس ای H + Bond O-H 0-0 C-O 0=0 C=O C-C C=C C=C C-H C-F C-Cl C-Br C-N C=N kJ. mol-¹ 464 142 351 502 730 347 615 811 414 439 331 276 293 615 Bond C=N N-H N-O N=N N=O F-F Cl-Cl Br-Br H-H H-F H-Cl H-Br H-S S-S kJ · mol-¹ 890 390 201 418 607 155 243 192 435 565 431 368 364 225 kJ.mol-¹