For converging and diverging lenses, there are 3 “fundamental” rays that can be traced to find the location and height of the image of an object. Please list these four rays, and give a picture for each one independent of the other rays.

A converging lens is placed 36.0 cm to the right of a diverging lens of focal length 7.0 cm. A beam of parallel light enters the diverging lens from the left, and the beam is again parallel when it emerges from the converging lens. Calculate the focal length of the converging lens. f = _____ cm

An object (height = 5.0 cm) and its image are on opposite sides of a converging lens. The object is located 11.0 cm from the lens. The image is located 5.3 cm from the lens. Determine the image height (in cm). Enter the numerical part of your answer to two significant figures. Hint: Remember that the sign of the image height is significant.

A 3 cm tall object is placed 16 cm from a converging lens with a focal length of 12 cm. A diverging lens with a focal length of 10 cm is placed 36 cm behind the converging lens. Both lenses have the same principal axis. Draw the ray diagram to graphically find the final image. Need only handwritten solution only (not typed one).

Thin lenses. Object O stands on the central axis of a thin symmetric lens. For this situation, each problem in the table (below) gives object distance p (centimeters), the type of lens (C stands for converging and D for diverging), and then the distance (centimeters, without proper sign) between a focal point and the lens. Find (a) the image distance i and (b) the lateral magnification m of the object, including signs. Also, determine whether the image is (c) real or virtual, (d) inverted from object O or noninverted, and (e) on the same side of the lens as object O or on the opposite side. (a) (b) (c) (d) (e) Lens i m R/V I/NI Side +14 C, 24 (a) Number Units (b) Number i Units (c) (d) (e) > >

A blue whale eyeball may be taken as a sphere that is about 15 cm in diameter. Assuming that it is filled with material with an index of refraction of 1.5, where would the image form for an object (in water) that is very far away? Just consider the initial image formed by refraction through the front surface. Select answer from the options below 15 cm behind the back of the eye 7.5 cm behind the front surface of the eye 15 cm behind the front surface of the eye Approximately 30 cm behind the back of the eye Approximately 50 cm behind the back of the eye

An object is located 50.0 m to the left a converging lens of focal length 15.0 cm. A diverging lens of focal length 4.20 cm is placed 10.0 cm to the right of the converging lens. Locate (final image position) and describe (real or virtual, upright or inverted, reduced or enlarged) the final image of the object formed by the two-lens system.

A 3.0 cm tall object is positioned 15.5 cm from a converging lens.  The focal length of the lens is 10.5 cm. What is the distance to the image? What is the magnification of the image? What is the height of the image? Is the image real or virtual? Is the image inverted or upright?

Leah and Arif now do a practice problem.Suppose you are in a partially darkened room holding a flat piece of white cardboard in one hand and a converging lens of focal distance 3.7  10-2 m in your other hand. You want to form an image of the window in front of you, which is at a distance of 2.34 m in front of the lens.How far behind the lens should the cardboard be held to form as sharp an image as possible? mIf the height of the window is 1.00 m, find the height of its image. m