Part A: State the characteristics of the image formed by a converging lens when the object is distance is less than the focal length of the lens. An object (2.0 mm high) is place at a distance of 30 cm in front of a diverging lens of focal length 20 cm.  Calculate the image distance of the image produced by the lens and verify all the characteristics listed in question (2).

- 20 cm. An object of height 2.5 cm is placed at 28 cm in front of a diverging lens of focal length, f = Behind the diverging lens, there is a converging lens of focal length, f = 20 cm. The distance between the lenses is 3 cm. In the next few steps, you will find the location and size of the final image. Hint a. Where is the intermediate image formed by the first diverging lens? Image distance from first lens is cm. (Use the sign to indicate which side the image is on; positive sign d;1 = means image is on the side of outgoing rays, and negative sign means image is on the side opposite to the outgoing rays.) b. Where is the final image formed by the second converging lens? Image distance from second lens is cm. (Use the sign to indicate which side the image is on.) di2 = c. How large is the intermediate image formed by the first diverging lens? Intermediate image height is cm. (Use the sign to indicate whether the image is upright (positive) or hil = inverted (negative).) = d. How…

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An object is located between a lens and a concave mirror as shown in Fig.4. The object is located at 15 cm to the left of the mirror whose radius of curvature is 25 cm. The mirror and the lens are separated at 50 cm. Then lens has a focal length of -10 cm. Assume that the object is imaged by the mirror first and subsequently by the lens. Determine the final image location with respect to the lens, its magnification and orientation. Is it virtual or real?