College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- True statements for optics Which of the following statements for single optic devices are true? Choose all that apply. It turns out that convex lenses always have a positive focal length. For real images, the image distance is negative and the object distance is positive. By convention, an inverted image has a positive image height. A magnification of -2 means the image is magnified. 0 Experiments have shown that converging optics can create virtual images. If an image has a magnification of -8, then the image is virtual. Which must be true? Using a single optic, an image with a negative image height is created. As a result, which of the following MUST be true? Choose all that apply. The image is real The image is virtual The image is inverted The image is upright The image distance is positive The image distance is negative The image has a positive magnification The image has a negative magnification The optic is converging The optic is diverging The optic has a positive focal length…arrow_forwardA 1.0-cmcm-tall object is 9.0 cmcm in front of a converging lens that has a 40 cmcm focal length. Calculate the image position. Express your answer with the appropriate units. Enter positive value if the image is on the other side from the lens and negative value if the image is on the same side as the object. Calculate the image height. Express your answer with the appropriate unitsarrow_forwardHow could you very quickly make an approximate measurement of the focal length of a converging lens? Could the same method be applied if you wished to use a diverging lens? Explain.arrow_forward
- A person looks at a gem using a converging lens with a focal length of 13.8 cm. The lens forms a virtual image 33.1 cm from the lens. Find the magnification. Describe the image. 1. real, upright, larger 2. real, inverted, larger 3. virtual, upright, larger 4. real, inverted, smaller 5. virtual, inverted, larger 6. real, upright, smaller 7. virtual, inverted, smaller 8. virtual, upright, smallerarrow_forwardThin lenses. Object O stands on the central axis of a thin symmetric lens. For this situation, each problem in the table (below) gives object distance p (centimeters), the type of lens (C stands for converging and D for diverging), and then the distance (centimeters, without proper sign) between a focal point and the lens. Find (a) the image distance i and (b) the lateral magnification m of the object, including signs. Also, determine whether the image is (c) real or virtual, (d) inverted from object O or noninverted, and (e) on the same side of the lens as object O or on the opposite side. (a) (b) (c) (d) (e) Lens i m R/V I/NI Side +14 C, 24 (a) Number Units (b) Number i Units (c) (d) (e) > >arrow_forward(Figure 1) shows an object and its image formed by a thin lens. Assume that L = 16.2 cm and y = 3.45 mm. Figure Image Object 6.00 cm L 1 of 1 Optic axis Lens Part A What is the focal length of the lens? Express your answer in centimeters. - ΑΣΦ f = Submit Part B What type of lens is it? Submit Request Answer converging diverging Part C II Request Answer What is the height of the image? Express your answer in millimeters. Π ΑΣΦ = ? ? cm mmarrow_forward
- You are having trouble reading your cheat sheet during your physics exam because you wrote so small. You foresaw the problem, so you brought a small lens with you to the exam. You hold the lens 6 cm away from the page. The image you see is upright and 2.9 times the size of the writing on the page. where is image formed Is the image real or virtual what is the focal length of the lens are you using a converting lens or a diverging lensarrow_forwardCase 5: Object located in focus (d0= F'). The figure below shows an arrow-shaped object, placed in front of a convex lens at a distance d0 equal to a focal length (d0=F'). Draw the following rays in the figure: ray parallel to the optical axis, central ray. Don't forget to put the direction on each ray, both the incident rays and the transmitted rays. Label each ray with its name. Image characteristics for Case 5: Object located in focus (d0= F'). Choose the ones that apply: a) Virtual b) Real c) Inverted d) Increased e) No image is formed f) Equal size g) Reduced h) Erect Case 6: Object located between the focus and the vertex of a convex lens (d0< F'). The figure below shows an arrow-shaped object, placed in front of a convex lens at a distance d0 less than a focal length (d0<F'). Draw the following rays in the figure: ray parallel to the optical axis, focal ray, central ray. Draw the image of the arrow, indicate in the same figure from where to where di is (image-lens…arrow_forwardProblem 1. A) An object is placed 2.5 cm before a converging lens of focal length 5 cm. Find the image position and magnification. B) Verify your answer to part A) by locating the image with a graphical ray trace. Use three different rays.arrow_forward
- A person looks at a gem using a converging lens with a focal length of 13.8 cm. The lens forms a virtual image 33.1 cm from the lens. Find the magnification. Describe the image. 1. real, upright, larger 2. real, inverted, larger 3. virtual, upright, larger 4. real, inverted, smaller 5. virtual, inverted, larger 6. real, upright, smaller 7. virtual, inverted, smaller 8. virtual, upright, smallerarrow_forwardChapter 34, Problem 034 SN When an object is placed a distance p in front of a spherical refracting surface with radius of curvature r, the image distance is i. If the index of refraction of the surrounding material Is n1, what is the index of refraction of the refracting material? State your answer in terms of the given variables. n2 = 2 Editarrow_forwardA small object is placed to the left of a convex lens and on its optical axis. The object is 46 cm from the lens, which has a focal length of 15 cm.Determine the location of the image formed by the lens. (Enter your answer in cm from the lens.) 1. cm from the lens 2. Describe the image.arrow_forward
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