Following is a sample of seven matched pairs. Sample 1 25 Sample 2 21 Send data to Excel Part: 0 / 4 12 19 11 18 and μ₂ represent the population means and let μ = μ₁-₂- Part 1 of 4 Let μ1 A test will be made of the hypotheses Ho: μ = 0 versus H₁: d>0. (a) Compute the differences. Sample 1 Sample 2 Difference 25 21 15 19 12 11 16 23 24 10 14 17 19 18 15 19 16 10 23 14 24 17

You wish to test the claim that u # 20 at a level of significance of a = 0.05 and are given sample statistics n 35, n = 35, x = 19.1, ands = 2.7. Compute the value of the %3D %3D %3D - %3D standardized test statistic using the formula

You wish to test the following claim (HaHa) at a significance level of α=0.01α=0.01.      Ho:μ1=μ2Ho:μ1=μ2      Ha:μ1≠μ2Ha:μ1≠μ2You obtain the following two samples of data. Sample #1 Sample #2 65.8 77.7 105.1 78.6 89.2 69.1 96.7 91.3 105.9 87.5 70.5 93.9 83.4 88.3 79.5 66.7 83.4 91.7 106.7 73 75.7 98.7 76.7 80 53.2 92.1 93 78.2 72.4 79.1 82.1 74.1 78.2 85.5 85.9 99.3 84.2 104.3 88.3 107.6 63.8 99.8 97.7 86.3 74.9 72.7 77.5 93.9 76.1 77.1 81.9 74.1 73.6 78.7 81.9 78.9 81.1 88 85.8 75.3 74.3 77.5 69.1 75.5 72.9 80.1 84.3 73.1 67.3 72.2 76.1 67.8 74.9 67.3 74.7 70.1 65.4 76.9 83.8 79.7 72.9 81.7 74.1 68.2 65.4 80.9 69.4 79.5 96 77.5 77.1 75.9 68.7       What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? For this calculation, use the degrees of freedom reported from the technology you are using. (Report answer accurate to four…

In order to compare the life expectancies of three different brands of tires, 5 tires of each brand were randomly selected and were subjected to standard wear-testing procedures. Information regarding the three brands is shown below.    Stone Bridge Michelle  Nice Year Mean mileage (in 1000 miles)  42 46 41 Sample variance 3 2 5 Sample Size 5 5 5 Use the above data and test to see if the mean mileage for all three brands of tires is the same. Let α = .05. Complete the ANOVA table and show the details of calculation. a) State the null and alaternative hypotheses to be tested. b) Complete the table. The null hypothesis is to be tested at 95% confidence. You need to show all calculations. What do you conclude?  Source of variation SS df  MS  F  F critcal value Between Treatment SSTR=   MSTR=     Within Treatment SSE=   MSE=     Total  SST=

1.3.2 Consider the output given below that was obtained using the One Proportion applet. Use information from the output to find the standardized statistic for a sample propor- tion value of 0.45. Probability of success (n): 0.30 Sample size (n): 25 Number of samples: 1000 O Animate Draw Samples Total = 1000 180 Mean = 0.301 SD = 0.091 120 60 0.08 0.16 0.24 0.32 0.40 0.48 0.56 0.64 Proportion of success

You wish to test the following claim (HaHa) at a significance level of α=0.01α=0.01.      Ho:μ1=μ2Ho:μ1=μ2      Ha:μ1<μ2Ha:μ1<μ2You obtain the following two samples of data. Sample #1 Sample #2 52 60.1 61.7 56.9 52 59.7 45 49.9 71.9 31.1 47.1 56.1 54.9 45 85.1 67 66.1 51.2 87.2 50.7 73.1 43.3 65.2 58.5 50.3 71.3 60.5 48 62.2 78.6 50.7 56.5 37.8 45.6 41.5 58.5 54.9 76.8 62.6 29.5 71.3 83.5 71.3 64.3 63 74.5 76.8 50.7 78.6 59.3 31.1 54.9 61.2 50.3 75.1 72.3 68.5 85.7 63.3 50.3 79.1 73.5 65.2 58.4 62.3 57 52.9 72.3 88.2 57.4 75.8 68.5 84.1 45 60 79.7 58.1 56.6 77.1 60.9 68.5 67.3 62 45 66.4 79.7 53.5 52.9 79.7 63.5 67.1 74.8 53.5 66.1 68.7 64.2 72.3 55.2 75.5   What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? For this calculation, use the degrees of freedom reported from the technology you are using. (Report answer…

10 11 12 13 14 15 16 Use a significance level of a=0.05 to test the claim that u = 19.6. The sample data consists of 10 scores for which x =20.1 and s=4.1. State the null and %3D alternative hypotheses, compute the value of the test statistic, and find the P-value for the sample. State your conclusions abcut the clalm. do H:H=19.6 H:Hz 19.6 O Test statistic: t=0.3856. P-Value: P=0.7087, Reject H. : u = 19.6. Since P>a, there is sufficient evidence to support the claim that the mean is different from 19.6. H :µ=20.1 H: Hz 20.1 O Test statistic: t= 20.1. P-Value: P=0.7087. Accept H: u = 20.1. Since P>a, there is not sufficient evidence to support the claim that the mean is different from 20.1. Ho: H= 19.6 H: uz 19.6 Submit Assignment Continue 2021 McGraw-Hill Education. All Rights Reserved. Terms of Use Privacy Accessibility DII & %24 7 t e f