First item. Just copy the entry I made below for the disposal of 250 mL of 4000 ppm palladium acetate solution (Pd as Pd(acetate)3) in hexane, which also contains about 10% acetic acid. This, in total, is three ingredients. I prefer to list each ingredient separately. So, this comes out to a. 250 mL hexane, b. 4000 mg/L x 0.250 L=1000 mg Pd(acetate)2, and c. 10%/100% x 250 mL = 25 mL acetic acid. I am including a screenshot of this first one for you to get the idea of how to deal with mixtures. I filled in the "general description", liquid and pH fields as well as the corrosive field. Again, notice where it says "with below" - this indicates that is twosolutes in one 250 mL solution.

First item. Just copy the entry I made below for the disposal of 250 mL of 4000 ppm palladium acetate solution (Pd as Pd(acetate)3) in hexane, which also contains about 10% acetic acid. This, in total, is three ingredients. I prefer to list each ingredient separately. So, this comes out to a. 250 mL hexane, b. 4000 mg/L x 0.250 L=1000 mg Pd(acetate)2, and c. 10%/100% x 250 mL = 25 mL acetic acid. I am including a screenshot of this first one for you to get the idea of how to deal with mixtures. I filled in the "general description", liquid and pH fields as well as the corrosive field. Again, notice where it says "with below" - this indicates that is twosolutes in one 250 mL solution.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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