Data we gather in the experiment Identity of metal Tin MEASUREMENT VALUE  Mass of metal, (g) 49.437   Trial 1 Trial 2 Mass of Styrofoam® cup and water, (g) 61.856 62.977 Mass of Styrofoam® cup, (g) 9.346 9.346 Mass of water, (g) ___________ ___________  Initial temperature of metal (temp of boiling water) (o C)  99.5 99.5 nitial temperature of water in cup,(o C) 21.5 22.9 Final  temperature  of  water  and  metal  (o C)       25.9 26.5 Specific heat of metal, (cal/go C) ___________ ___________ Average specific heat of metal, (cal/go C)                           ___________     Calculations:   ΔTwater = Tf – Ti water =  ____oC         ΔTmetal = Tf – Ti metal  = _         oC         Qwater = (1.00 cal/go C) x (           g water) x (            oC) =                    cal Qmetal = – Qwater     Cmetal = Qmetal / (mmetal x ∆Tmetal )= – _______cal / [(______g) x (_____oC)] = ________cal/goC

Chemical Principles in the Laboratory
11th Edition
ISBN:9781305264434
Author:Emil Slowinski, Wayne C. Wolsey, Robert Rossi
Publisher:Emil Slowinski, Wayne C. Wolsey, Robert Rossi
Chapter6: Properties Of Hydrates
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Problem 1ASA: A student is given a sample of a pink manganese (II) chloride hydrate. She weighs the sample in a...
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Data we gather in the experiment

Identity of metal

Tin

MEASUREMENT

VALUE

 Mass of metal, (g)

49.437

 

Trial 1

Trial 2

Mass of Styrofoam® cup and water, (g)

61.856

62.977

Mass of Styrofoam® cup, (g)

9.346

9.346

Mass of water, (g)

___________

___________

 Initial temperature of metal (temp of boiling water) (o C) 

99.5

99.5

nitial temperature of water in cup,(o C)

21.5

22.9

Final  temperature  of  water  and  metal  (o C)

 

 

 

25.9

26.5

Specific heat of metal, (cal/go C)

___________

___________

Average specific heat of metal, (cal/go C)

 

                        ___________

 

 

Calculations:

 

ΔTwater = Tf – Ti water =  ____oC

 

 

 

 

ΔTmetal = Tf – Ti metal  = _         oC      

 

Qwater = (1.00 cal/go C) x (           g water) x (            oC) =                    cal Qmetal = – Qwater

 

 

Cmetal = Qmetal / (mmetal x ∆Tmetal )= – _______cal / [(______g) x (_____oC)] = ________cal/go

 

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