DATA/CALCULATION SHEET NAME 1. crucible, cover, BaCl2 2H2O \$,2061 crucible and cover 14.0188g BaCl2 2H2O 4.1873 8 first second third weighing weighing weighing crucible, cover, anhydrous BaCl2 17,5815 H2O lost (use your last weighing) 17.58158 SHOW CALCULATION % water, experimental (See prelab) % water, theoretical SHOW CALCULATION % error

DATA/CALCULATION SHEET NAME 1. crucible, cover, BaCl2 2H2O \$,2061 crucible and cover 14.0188g BaCl2 2H2O 4.1873 8 first second third weighing weighing weighing crucible, cover, anhydrous BaCl2 17,5815 H2O lost (use your last weighing) 17.58158 SHOW CALCULATION % water, experimental (See prelab) % water, theoretical SHOW CALCULATION % error

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Perform the following calculations to the correct number significant figures. (23.4813 x 2.52) + 374.99
/1wdGaF3fc41TY-3NU4JhvIQJLK2kFekLX/edit minutes ago IUA 三 ==,E 三E|X 20 2 | E 3 LI 4 IT3 E OI I 7 + EXPERIMENT Percent vield Due after completing the lab. Answer in the space provided. 1. A student reacted 0.500 g of Pb(NO.)2 with 0.750 g of KI according to the reaction, Pb(NO.b (aq) + 2 KI (aq)- → Pbb (s) +2 KNO: (aq) How many moles of Pb(NO.)2 were used? mol of Pb(NO) b) How many moles of KI were used? mol of KI c) How many moles of PbL would form, based on mol of Pbb the moles of Pb(N0) used? d) How many moles of Pbl would form, based on mol of Pbl the moles of KI used? e) Which is the limiting reactant? What is the theoretical yiekd of PbL in grams? 主 g of PbL g) If the student obtained 0.583 grams of PbL product after collecting it by fihration and dry ing it, what was the percent yield of Pbl obtained? 2. Diborane, B H, can be produced by the following reaction: NaBH (aq) H 50 (a) = H (g) = Na SO (aql= BH(B) What is the maximum quantity, in grams, of B H that can be prepared…
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ll T-Mobile ? 11:32 PM O 1 35% 23obrien... Name Date Period CHE Worksheet: Avogadro's Number and The Mole Helpful information: I mole- 6,02 x 10" atoms, molecules, or formula units (particles) Conversion Factors: I mole 6.02 x 10" particles 6.02 x 10" particles I mole Complete the calculations using dimensional analysis. Show all work! 1. How many atoms of zinc are found in 2.50 mols of zine? 2. How many molecules are found in 11.5 mols of water? 3. How many particles of AgNO, are found in 3.25 mols of AgNO,? 4. How many moles of Al are found in 5.75 x 10 Al atoms? 5. How many moles of Fe are found in 2.50 x 10 Fe atoms? 6. How many moles of sugar are found in 6.78 x 10" sugar molecules?
4) An electric furnace produces Mn from Mn3O4 by reaction with carbon. If 40 kg Mn3O4 reacts with 12 kg of carbon and produces 18 kg Mn, 8 kg MnO, CO gas and some reactants have no reaction, Determine: a. The amount of Mn;04 and C with no reaction in kg. b. The amount of CO in kg is produced. Information: C= 12, 0= 16, Mn=55 40 kg = Mn;O4 CO (gas) Furnace 12 kg = C Mn = 18 kg MnO=8 kg Solid C Mn304
HAPTER 3 - CHEMICAL REACTIONS Study Page 1 of 3 Next O References Use the References to access important values if needed for this question. hen the following molecular equation is balanced using the smallest possible integer coefficients, the values of these coefficients are: sulfur (s) + carbon monoxide (g) sulfur dioxide (g) + carbon (s) sp.cengage.info/als-asp/take a 80°F O Type here to search Ca
mistry app.101edu.co YouTube Maps NG AMOUNT * @ 7 2 X W S F2 X Jill # Welcome to MyTCC Welcome to MyTCC 3 F3 E D C 20: $ 4 R F 30 % 35.6 V Aluminium has a density of 2.70 g/cm² How many moles of aluminum are in a 13.2 cm block of the metal substance? 4 ADD FACTOR X x() F5 5 molecules Al T Content G 1.32 F6 A 6 B 2.70 0.489 g Al/mol F7 Y & H Question 1 of 50 0.100 g/cm² W 7 26.98 N ASUS X F8 U J g Al Lo b Home | bartleby ANSWER 8 962 13.2 F9 | M mol Al 1 1 K F10 9 < I RESET 5 6.022 x 10 O cm 1 F11 O L X + 10 P : F12 - I Prt Sc 1 ? + [ Q 12 ☆ = 12 Insert 1 Delete Backspace J Submit Home Enter PgUp Shift Pe
Imole 1,5g Cu 504,3 X Imole ('u 5 0415H20 = Moles of anhydride used. (Show calculations) = Cu Soy • 5H20(s) A ('u 504 (5) + 5H20 (9) Hydrate » anhydride Moles of H₂O of hydration (Show calculations)= Ratio of moles of water to moles of anhydride (Show calculations.) = Molarmass = (to correct sig. figs. - do not round yet) Based on your data, what is the empirical formula of your hydrate (round your ratio to the closest whole number)? Use the Argumentation Framework (see inside front cover) (Claim- Evidence- Justification) to justify your answer. 147 S 112 52
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Volume (mL) Trial 1 Trial 2 Trial 3 Final volume (mL) 24.35 47.60 20.60 Initial volume (mL) 1.25 25.15 42.85 Volume Added 23.10 22.45 22.35 Average Volume Added 22.63 mL Concentration of NaOH 0.9971 M % Acetic Acid in Vinegar Assuming all the acid to be acetic, calculate the number of grams of acid per 100 mL of vinegar solution. Assuming that the density of vinegar is 1.000, what is the percentage of acetic acid by weight in vinegar? Average your results in the usual manner. % of Acetic Acid = (mL of NaOH added)(concentration of NaOh)/mL of vinegar sample