Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Mole Concept
Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can b…
Question
**Problem Statement:** Find \( v_{\text{rms}} \) for nitric oxide gas (NO) at 25°C. **Periodic Table Information:** - Oxygen (O): Atomic number: 8, Atomic mass: 16.00 - Nitrogen (N): Atomic number: 7, Atomic mass: 14.01 **Answer Choices:** A. \( 497.8 \, \text{m/s} \) B. \( 600.1 \, \text{m/s} \) C. \( 405.0 \, \text{m/s} \) D. \( 527.3 \, \text{m/s} \) E. \( 594.7 \, \text{m/s} \) F. \( 403.7 \, \text{m/s} \)
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Transcribed Image Text:**Problem Statement:** Find \( v_{\text{rms}} \) for nitric oxide gas (NO) at 25°C. **Periodic Table Information:** - Oxygen (O): Atomic number: 8, Atomic mass: 16.00 - Nitrogen (N): Atomic number: 7, Atomic mass: 14.01 **Answer Choices:** A. \( 497.8 \, \text{m/s} \) B. \( 600.1 \, \text{m/s} \) C. \( 405.0 \, \text{m/s} \) D. \( 527.3 \, \text{m/s} \) E. \( 594.7 \, \text{m/s} \) F. \( 403.7 \, \text{m/s} \)
Expert Solution
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Step 1 To Calculate

Given, temperature =25 °C =(25+273.15) K =298.15 KMolar mass of nitric oxide =30.01 g/mol =0.03001 kg/molgas constant =8.314 Jmol.Kwe are asked to calculate the Vrms for nitric oxide at 25 °C 

Step 2 Formula used and Calculations

The Vrms of nitric oxide gas is given by,Vrms =3RTM  ; where, R is gas constant, T is temperature and M is molar mass of gas.Now, Vrms =3RTMVrms =3×8.314 Jmol.K×298.15 K0.03001 kgmolVrms =7436.4573 kg.m2sec20.03001 kg   (1J =1kg.m2sec2)Vrms =247799.3102 m2sec2Vrms =497.794 msecVrms =497.8 msecThus, the Vrms for nitric oxide at 25 °C would be, 497.8 msec

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