Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Transcribed Image Text:Find the apparent Km and apparent Vmax for the enzyme reaction containing
the inhibitor and identify the type of inhibitor
The increment on the X axis is 25uM
The increment on the Y axis is 8 sec uM
We
VISI
O appvmax-0.05microM/sec; appKm=0.02microM: mixed
O appvmax-0.05microM/sec; appKm=0.02microM; uncompetitive
O appvmax-0.075microM/sec, appKm-0.013microM; competitive
O appvmax-0.05microM/sec; appKm-0.013microM; uncompetitive
O appvmax 75microM/sec; appKm-13.3microM; uncompetitive
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- From the following data (ESSAY DPPH & METHANOL), make a graph of the adjusted model Concentration (x-axis) vs. % inhibition (y-axis), provide the equation that is given and explain its behavior in a broad way. Do this activity step by step pleasearrow_forwardWhen the reactions in part (B) are repeated in the presence of 12 ?M of an uncompetitive inhibitor, the y - intercept of the Lineweaver - Burk plot is 0.352 (?mol? 1mls). Calculate K? for this inhibitor. I tried 0.187 and it was off. Not sure what units to use either.arrow_forwardIf inhibitor X changes lactase activity to a Vo of 0.10 mM per minute when [S] = 1.0 mM, and a Vo of 0.133333333333 mM per minute when [S] = 2.0 mM, calculate the new Vmax. Calculate the new Km of the above lactase reaction, with inhibitor X. Calculate the slope on a Lineweaver-Burk plot (Km / Vmax) for the lactase reaction with inhibitor X. Inhibitor X exerts which of the following effects on the above enzyme (lactase)?arrow_forward
- Only typed solutionarrow_forwardCalculate the slope on a Lineweaver-Burk plot (Km / Vmax) for the lactase reaction with inhibitor X. (inhibitor X changes lactase activity to a Vo of 0.10 mM per minute when [S] = 1.0 mM, and a Vo of 0.133333333333 mM per minute when [S] = 2.0 mM) 0.20 per minute 0.50 per minute 1.0 per minute 2.0 per minute 5.0 per minutearrow_forwardIR PAP Chemnistr x G diagram show X PAP Chemistry x G What is the be x E PAP Chemistr x E PAP Chemistr x -a Session Timex Mp Rockin a ar-2903012.agilixbuzz.com/student/135113422/activity/c412d902-b23e-4202-b813-76a1f9f4c196 Mastery Assess It 8 que Solis PAP Chemistry-2903012-42100P-1/Le Chatelier's Principle / Lesson 128 All changes saved 8. A chemist tested the reaction of potassium chlorate (KCIO3) and Iron (II) sulfate (FeSo). The Independent varlable is temperature; all other variables are constant. The results were recorded. Temperature (degrees Kelvin) Reaction Rate (grams per second) 285 290 295 These results support which conclusion? O An increase in temperature increassed the mass of each molecule of reaction product. An increase in temperature increased the amount of reactant present. O An increase in temperature increased the catalytic behavior of reactants. O An increase in temperature increased the rate of collision of reactant molecules. PREVIOUS 8 of 25 NEXT SAVE & EXIT…arrow_forward
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