whats the 2.303 for

Fundamentals Of Analytical Chemistry
9th Edition
ISBN:9781285640686
Author:Skoog
Publisher:Skoog
Chapter7: Statistical Data Treatment And Evaluation
Section: Chapter Questions
Problem 7.17QAP
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whats the 2.303 for 

» tye
t2 = 20.9 Hns
typ =
0.693/K
k =
0•693
0.603/ 20.9
K
= 0. 033 hit"
%3D
k = 3.3 X/0-2 hri!
Transcribed Image Text:» tye t2 = 20.9 Hns typ = 0.693/K k = 0•693 0.603/ 20.9 K = 0. 033 hit" %3D k = 3.3 X/0-2 hri!
Step 2
t2 = 20.9 Hns
ty2 = 0.603/K
k =
0•693
%3D
= 0:603/20-9
0.693
K
= 0: 033 hit
%3D
k = 3.3 X10-2 hr
r!
") t =
2.30 3
%3D
てime
Transcribed Image Text:Step 2 t2 = 20.9 Hns ty2 = 0.603/K k = 0•693 %3D = 0:603/20-9 0.693 K = 0: 033 hit %3D k = 3.3 X10-2 hr r! ") t = 2.30 3 %3D てime
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