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Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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![Fill in the proper reagents to complete the synthesis reaction below. Be sure to make sure you have
the right reactions in the proper order!
d
[Select]
[Select]
H3CO.
You may use any of the following reagents: HBr, HBr with peroxide, H₂ on palladium, CH3OH,
NaOCH 3, CH3l.](https://content.bartleby.com/qna-images/question/8de6a7b5-a4ea-4b0b-8dec-fa26532813fc/812c930d-209c-42ff-b1e4-7e19322a0a49/k81nmfp_thumbnail.png)
Transcribed Image Text:Fill in the proper reagents to complete the synthesis reaction below. Be sure to make sure you have
the right reactions in the proper order!
d
[Select]
[Select]
H3CO.
You may use any of the following reagents: HBr, HBr with peroxide, H₂ on palladium, CH3OH,
NaOCH 3, CH3l.
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- 1. Provided below is the structure of the minor product of the electrophilic addition reaction. Provide a mechanism to account for its formation. Br. он Ph—с—с—н Ph H the minor productarrow_forwardDraw the product of the reaction between 2-pentanol and PBrą. ● ● ● ● You do not have to consider stereochemistry. You do not have to explicitly draw H atoms. Do not include counter-ions, e.g., Na+, I-, in your answer. If no reaction occurs, draw the organic starting material. Sn [F ? ChemDoodleⓇarrow_forwardCan you show the mechanism?arrow_forward
- Write a mechanism for this reaction below.arrow_forwardThe following reaction involves two sequential Heck reactions. Draw structural formu- las for each organopalladium intermediate formed in the sequence and show how the final product is formed. Note from the molecular formula given under each structural formula that this conversion corresponds to a loss of H and I from the starting material. Acetonitrile, CH,CN, is the solvent. 1% mol Pd(OAc), 4% mol Ph,P CH,CN C4H171 C4H16arrow_forwardWhy is a strong acid (like HCI) used in a Grignard reaction? O 1) A strong acid is used in the Grignar reaction in order to protonate the carbonyl in order to make a better leaving group, OH. Once teh OH leaves, the alcohol group is reformed due to water. A stable tetrahedral intermediate with a negatively charged oxygen forms O 2) that does not possess a leaving group. This intermediate will exist until a proton source from the strong acid protonates the negatively charged oxygen, affording the neutral alcohol product. 3) The use of a strong acid is not necessary. It is simply recommended as it increases the yield produced in the reaction. 4) The use of a strong acid is necessary for the formation of a Grignard reagent. Without a strong acid, the organomagnesium compound cannot be formed.arrow_forward
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