Figure P15.49 shows a closed cylinder with cross-sectional area A = 2.00 m². The con- stant electric field É has mag- nitude 3.50 x 10% N/C and is directed vertically upward, perpendicular to the cylinder's top and bottom surfaces so that no field lines pass through the curved surface. Calculate the electric flux through the cylinder's (a) top and (b) bottom surfaces. (c) Determine the amount of charge inside the cylinder. Figure P15.49

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
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Chapter25: Gauss’s Law
Section: Chapter Questions
Problem 33PQ: Figure P25.33 shows a very long, thick rod with radius R, uniformly charged throughout. Find an...
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Figure P15.49 shows a closed
cylinder with cross-sectional
area A = 2.00 m². The con-
stant electric field É has mag-
nitude 3.50 x 10% N/C and
is directed vertically upward,
perpendicular to the cylinder's
top and bottom surfaces so that no
field lines pass through the curved
surface. Calculate the electric flux
through the cylinder's (a) top and
(b) bottom surfaces. (c) Determine
the amount of charge inside the
cylinder.
Figure P15.49
Transcribed Image Text:Figure P15.49 shows a closed cylinder with cross-sectional area A = 2.00 m². The con- stant electric field É has mag- nitude 3.50 x 10% N/C and is directed vertically upward, perpendicular to the cylinder's top and bottom surfaces so that no field lines pass through the curved surface. Calculate the electric flux through the cylinder's (a) top and (b) bottom surfaces. (c) Determine the amount of charge inside the cylinder. Figure P15.49
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