A Gaussian surface in the form of a hemisphere of radius R = 5.84 cm lies in a uniform electric field of magnitude E = 2.20 N/C. The surface encloses no net charge. At the (flat) base of the surface, the field is perpendicular to the surface and directed into the surface. (a) What is the flux through the base? ______________N · m2/C(b) What is the flux through the curved portion of the surface? _______________N · m2/C

A Gaussian surface in the form of a hemisphere of radius R = 5.84 cm lies in a uniform electric field of magnitude E = 2.20 N/C. The surface encloses no net charge. At the (flat) base of the surface, the field is perpendicular to the surface and directed into the surface. (a) What is the flux through the base? N · m2/C(b) What is the flux through the curved portion of the surface? _N · m2/C

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter25: Gauss’s Law

Section: Chapter Questions

Problem 49PQ

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