F2 F1 FO Functionality 0 0 0 ADD the value on the A bus to the value on the B bus 0 0 1 AND the value on the A bus to the value on the B bus 0 1 0 0 1 1 LEFT SHIFT the value on the B bus by the number of bits specified on the A bus RIGHT SHIFT the value on the B bus by the number of bits specified on the A bus INCREMENT the value on the A bus by 1 1 0 0 1 0 1 IF DO = 1 THEN B ELSE O 1 1 0 SET output of the ALU to 0 1 1 1 SET the output of the ALU to the value on the B bus Table 1: ALU functions _ C0=1, C1=1 B0=1, B1=1 D3 CO=1, C1=0 D2 12 B0=1, B1=0 CO=0, C1=1 D1 B0=0, B1=1 C0=0, C1=0 DO 80 C A B F2 8-bit ALU Figure 1: 8-bit data-path FO

QUESTION 5 35 A convolutional circuit has three internal registers (s0, s1, and s2), and two outputs (c0 and c1), calculated as follows: c0=i+s2; c1=i+s0+s1. We are currently in state 110 and receive input 0. What is the output and next state? O c0=0; c1=0; next=011 O c0=1; c1=0; next=011 O c0=1; c1=1; next=011 O c0=0; c1=1; next=011 QUESTION 6 11 A convolutional circuit has three internal registers (S0, S1, and s2), and two outputs (c0 and c1), calculated as follows: c0=i+s0; c1=i+s1+s2. We are currently in state 110 and receive input 0. What is the output and next state? O c0=1; c1=1; next=011 O c0=0; c1=1; next=011 O c0=0; c1=0; next=011 O c0=1; c1=0; next=011 QUESTION 7 02 A convolutional circuit has three internal registers (s0, s1, and s2), and two outputs (c0 and c1), calculated as follows: c0=i+s0; c1=i+s0+s1. We are currently in state 011 and receive input 1. What is the output and next state? O c0=0; c1=1; next=101 O c0=0; c1=0; next=101 O c0=1; c1=0; next=101 O c0=1; c1=1;…

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The circuit below is a 4-bit shifter with 2 control inputs s1 and s0, 4 data inputs 13, 12, 11, and 10, and 4 data outputs Q3, Q2, Q1, and Q0. If the input 13 12 11 10 = 1101, what is the final output when s1 s0 = 01 and then 11 next clock cycle ? 13 12 I1 IO s1 s0 Q3 Q2 Q1 QO 0000 0010 0110 O 1010

Using Logism for otherwise complete the attached 8 bit alu  The Arithmetic Logic Unit The most important and possible most difficult component to implement is the arithmetic logic unit. Thefunctions of the ALU are shown in Table 1. The ALU should have 5 inputs (A-input, B-input, F0-input, F1-input, Finput) and 1 output (C-output). You will need to determine how many bits each input and output should have.Remember, you are designing an 8-bit microprocessor! . For example, to add the value on the A-bus8-bit ALUto the value on the B-bus, you can simply use an 8-bit adder. Explore the components in Logisim! Additionally,you can think about using a multiplexer to determine which ALU function will be performed

• Design a sequential circuit with two T Flip Flops, A and B, and two inputs, E and x. If E=0, the circuit remains in the same state regardless of the value of x. When E=1 and x=1, the circuit goes through the state transitions from 00 to 01 to 10 to 11 back to 00, and repeats. When E=1 and x=0, the circuit goes through the state transition from 00 to 11 to 10 to 01 back to 00, and repeats

Design and implement (draw the circuit) the output f(12) of a 7 segments decoder as a function of the binary inputs (W,X,Y,Z). You need the complete the following steps: 1. Find the f(12) outputs values (0 or 1) for each number from 0-11 2. Enter these values into a Karnaugh map. 3. Simplify the map. 4. Draw the circuit using Tina. 7 segments display decoder. 7 segments 4 Binary inputs a 7 Segments Decoder Y e

I believe this problem is from computer systems/architecture. PLEASE TRY YOUR BEST. I NEED TO UNDERSTAND THIS PROBLEM I need you to design a digital logic circuit as a read only memory (ROM) [Decoder + OR gates]. A ROM accepts a three–bit number (x2 x1 x0) and generates an output binary number equal to the input squared + 2. Here is the equation: A = x2 + 2, with input (x) : 0 ≤ (x) ≤ 7 (a) Try to set–up the truth–table [Binary inputs: (x); Binary outputs: ..., A2, A1, A0] (b) What is the size of the initial (unsimplified) ROM ? (c) What is the size of the final (simplified) ROM ?

Draw a 4-input adder for single-bit values: that is, a set of logic gates with 4 input wires each representing a number between 0 and 1 and a multi-bit output z, composed of wires z0 through z... (where z0 is the low-order bit, z1 the next, etc., up to the number of wires needed for this task). The gates should ensure that z = the sum of all four inputs.

How does the width of a register relate to the number of D-flip-flops used in the circuit? Each register is implemented with one D-flip-flop, regardless of the width of the register. Each bit in the register corresponds to two D-flip-flops. Each bit in the register corresponds to a D-flip-flop, so it is 1-to-1. Since D-flip-flops have a Q and Qn output, you only need 1 D-flip-flop for each bit in the register.