F1 and F2 offspring with given genders and disease phenotypes. The data are generated from an initial parental cross. One parent displays the disease phenotype and one displays the wild-type (WT) phenotype. The WT parent always has a homozygous genotype. There are three possible modes of inheritance that underlie the generation of the data. All are monogenic. They are: (i) Autosomal Recessive. (ii) Homozygous Lethal Dominant. (iii) Autosomal Dominant. One's phenotype is determined by their genotype at the disease locus and the mode of inheritance, as we have seen with Punnett Square. on the F2 data and make a decision, based on your statistical analysis, as to whether you reject or do not reject the computer-generated model of inheritance as being consistent with the observed data. The mode of inheritance you are to test on the observed data is autosomal recessive. PARENTAL CROSS Parental cross: Father with disease phenotype, Mother with wild-type phenotype. F1 DATA Phenotype Gender Disease Wild-Type Male 49 0 Female 61 0 F2 DATA Phenotype Gender Disease Wild-Type Male 39 15 Female. 45 11 Gender Phenotype Observed counts (O) Expected Proportions Expected Counts (E) (O-E) (O-E)^2/E Male WT Male Disease Female WT Female Disease Total DegFrdm P-value In typed please with calculations.
F1 and F2 offspring with given genders and disease
The data are generated from an initial parental cross.
One parent displays the disease phenotype and one displays the wild-type (WT) phenotype.
The WT parent always has a homozygous genotype.
There are three possible modes of inheritance that underlie
the generation of the data. All are monogenic. They are:
(i) Autosomal Recessive.
(ii) Homozygous Lethal Dominant.
(iii) Autosomal Dominant.
One's phenotype is determined by their genotype at the disease locus
and the mode of inheritance, as we have seen with Punnett Square.
on the F2 data and make a decision, based on your statistical analysis, as to whether
you reject or do not reject the computer-generated model of inheritance as being consistent
with the observed data.
The mode of inheritance you are to test on the observed data is autosomal recessive.
PARENTAL CROSS
Parental cross: Father with disease phenotype, Mother with wild-type phenotype.
F1 DATA
Phenotype
Gender Disease Wild-Type
Male 49 0
Female 61 0
F2 DATA
Phenotype
Gender Disease Wild-Type
Male 39 15
Female. 45 11
|
Gender |
Phenotype |
Observed counts (O) |
Expected Proportions |
Expected Counts (E) |
(O-E) |
(O-E)^2/E |
|
Male |
WT |
|||||
|
Male |
Disease |
|||||
|
Female |
WT |
|||||
|
Female |
Disease |
|||||
|
Total |
||||||
|
DegFrdm |
||||||
|
P-value |
In typed please with calculations.
Step by step
Solved in 3 steps
