Related questions
Question
The force acting on a particle varies as in the figure below. (The x axis is marked in increments of 5.00 m.)
Find the work done by the force as the particle moves across the following distances.
(a) from x = 0 m to x = 40.0 m
(b) from x = 40.0 m to x = 60.0 m
(c) from x = 0 m to x = 60.0 m
Transcribed Image Text:F, (N)
B.
x (m)
-2
4.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution
Trending nowThis is a popular solution!
Step by stepSolved in 3 steps
Knowledge Booster
Similar questions
- A variable force F(x) = ax, in which a = 3.0 N/m, acts on an object. Calculate the work done by this force as the object travels from x1 = 1.5 m to x2 = 3.4 m, in joules.arrow_forwardThe force acting on a particle varies as in the figure below. (The x axis is marked in increments of 1.50 m.) Find the work done by the force as the particle moves across the following distances. (a) from x = 0 m to x = 12.0 m (b) from x = 12.0 m to x=18.0m (c) from x = 0 m to x=18.0marrow_forwardA shopper in a supermarket pushes a cart with a force of 41 N directed at an angle of 25° below the horizontal. The force is just sufficient to overcome various frictional forces, so the cart moves at constant speed. (a) Find the work done by the shopper as she moves down a 42.0-m length aisle. Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. J (b) What is the net work done on the cart? Why? This answer has not been graded yet. (c) The shopper goes down the next aisle, pushing horizontally and maintaining the same speed as before. If the work done by frictional forces doesn't change, would the shopper's applied force be larger, smaller, or the same? What about the work done on the cart by the shopper? This answer has not been graded yet.arrow_forward
- A man cleaning his apartment pushes a vacuum cleaner with a force of magnitude 35.8 N. The force makes an angle of 34.5 with the horizontal floor. The vacuum cleaner is pushed 3.76 m to the right along the floor. Calculate the work done by the 35.8 N force. Answer in units of J.arrow_forwardA block of mass m = 2.50 kg is pushed d = 2.70 m along a frictionless horizontal table by a constant applied force of magnitude F = 18.0 directed at an angle ? = 25.0° below the horizontal (a) Determine the work done by the applied force.= J (b) Determine the work done by the normal force exerted by the table.= J (c) Determine the work done by the force of gravity.= J (d) Determine the work done by the net force on the block.= Jarrow_forwardA shopper in a supermarket pushes a cart with a force of 33.0 N directed at an angle of 25.0° below the horizontal. The force is just sufficient to balance various friction forces, so the cart moves at constant speed. Find the work done by the shopper on the cart as she moves down a 54.2-m-long aisle. The shopper goes down the next aisle, pushing horizontally and maintaining the same speed as before. If the work done by frictional forces doesn't change, would the shopper's applied force be larger, smaller, or the same? What about the work done on the cart by the shopper? Is the work larger in part a, or is the work larger in part b; or is the work the same in both parts?arrow_forward
- The force acting on a particle varies as shown in the figure below. (The x axis in the graph has its tickmarks marked in increments of 2.50 m.) F, (N) B. 4 A Ex (m) -2 D Find the work done by the force on the particle as it moves across the following distances. (a) from x = 0 m to x = 20.00 m (b) from x = 20.00 m to x = 30.00 m (c) from x = 0m to x = 30.00 m Jarrow_forwardA block of mass m is lowered down a surface inclined at θ degrees for a distance d between points A and B. A horizontal force F is acting on the block between A and B. Take the kinetic energy of the block at points A and B as KA and KB, respectively. (a) Construct an analytic expression to determine how much work is done on the block by the force of friction between points A and B.arrow_forwardThe force component along the displacement varies with the magnitude of the displacement, as shown in the graph. Find the work done by the force in the interval from (a) 0 to 0.9 m, (b) 1.0 to 2.0 m, and (c) 2.0 to 3.8 m. (Note: In the last interval the force component is negative, so the work is negative.)arrow_forward
- A force given by (6i – 3j) N acts on an object experiencing a displacement given by (3i – j) m. Determine the work done by the force.arrow_forwardAn object of mass 3.00 kg is subject to a force E, that varies with the position as in the figure below. (a) Find the work done by the force on the object as it moves from x = 0 to x = 5.00 m. (b) Find the work done by the force on the object as it moves from x = 5.00 m to x = 12.0 m. (c) Find the work done by the force on the object as it moves from x = 12.0 m to x = 17.0 m. (d) If the object has a speed of 0.400 m/s at x 0, find its speed at x = 5.00 m and its speed at x = 17.0 m. F, (N) 4 3 2 x (m) 4 8 10 12 14 16 18 20arrow_forwardA particle is subject to a force Fx that varies with position as shown. Find the work done by the force on the particle as it moves (a) from x = 0 to x = 5.00 m, (b) from x = 5.00 m to x = 10.0 m, and (c) from x = 10.0 m to x = 15.0 m. (d) What is the total work done by the force over the distance x = 0 to x = 15.0 m?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios