Explain why telomeres and telomerase are needed for replication of eukaryotic chromosomes but not for replication of a circular bacterial chromosome. draw a diagram to illustrate your explanation.

Using the illustration of DNA replication given below label the following:

In your own words

DNA replication is vital for successful cell division. Explain the process of DNA replication. Make sure to use the following terms: helicase, S-phase, DNA polymerase and DNA ligase, template, free nucleotides. Use the diagram if it helps you illustrate your points.

Define DNA replication/synthesis and semiconservative replication.  In addition, describe and/or define the role(s) of each of the following in the process of DNA replication/synthesis: DNA template strand, 5’ and 3’ ends, DNA helicase, DNA polymerase, single-strand binding proteins, topoisomerase, primase, Okazaki fragments, leading strand and lagging strand.

(d) Write down the sequences of the templates that would give the tetranucleotides shown in I and II. In each case, label the 5' and 3' ends and indicate which template base is used first. (e) What difference would it make to bidirectional DNA replication if both modes of chain extension were equally favourable? I II

How many times would telomerase have to bind to a different site in the telomere to make a segment of DNA that is 36 nucleotides in length?

Describe heterochromatin and euchromatin when viewed under an electron microscope

Match the enzyme on the left with its role in DNA replication DNA polymerase I helicase DNA ligase DNA polymerase III topoisomerase primase 72 W w# 3 E $ 4 R % 5 T A 6 MacBook Pro Y & 7 U * 8 replaces primers with DNA connects Okazaki fragments to form a continuous strand of DNA synthesizes short RNA fragments used to initiate DNA synthesis Uses the 3'OH of an RNA primer to synthesize the leading strand and Okazaki fragments keeps DNA from getting tangled up ahead of the replication fork "unwinds" the DNA double helix at the origin and replication forks 1 ( 9 X 0 0 P + 11 Next

DNA polymerase occasionally incorporates the wrong nucleotide during DNA replication. If left unrepaired, the base-pair mismatch that results will lead to mutation in the next replication. As part of a template strand, the incorporated wrong base will direct the incorporation of a base complementary to itself, so the bases on both strands of the DNA at that position will now be different from what they were before the mismatch event. The MER-minus strain of yeast does not have a functional  mismatch excision repair system, but it has normal base excision repair and nucleotide excision repair systems. Which of the following statements is correct about differences in the mutation spectrum between MER-minus and wildtype yeast? More than one answer is correct. Options:   More point mutations will arise in MER-minus yeast.   Fewer point mutations will arise in MER-minus yeast as compared with wildtype.   Of the total point mutations that…