Scenario. Three specimen of D12 rebar was subjected to a Tensile Test. Using a steel density of8000Kg/cu.m. With the following resultspecimen 1specimen 2M=0.895 kgM=0.89 kgL=98 cmL=99 cmLoad at yield strength= 5000 kgLoad at ultimate =8600 kgGauge length after test=21.5 cmLoad at yield strength= 5000 kgLoad at ultimate =8600 kgGauge length after test=21.6 cmspecimen 3M=0.897 kgL=100 cmLoad at yield strength= 5010 kgLoad at ultimate strength=8590 kgGauge length after test=21.6 cmspecimen Yield strengthYield strengthUltimate strength Ultimate strength STRAINbased on actual based on 12mmbased on actualbased on 12mmdiameter (MPa)diameter (MPa)diameter (MPa)diameter (MPa)1.2.average

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specimen Yield strength based on actual Yield strength based on 12mm based on actual diameter (MPa) diameter (MPa) Ultimate strength Ultimate strength STRAIN based on 12mm diameter (MPa) diameter (MPa)

specimen Yield strength based on actual Yield strength based on 12mm based on actual diameter (MPa) diameter (MPa) Ultimate strength Ultimate strength STRAIN based on 12mm diameter (MPa) diameter (MPa)

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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40)A tensile test specimen has a gage length=3.0 inches and a diameter= .75 inches. Yielding occurs at a load of 38000lbs. The corresponding gage length=3.0103 inches (neglect the .0.2% yield point). The maximum load of 54000lbs i9s reached at a gage length =3.453 inches. If the specimen necked down to a diameter=.645 inches, determine the percent reduction in area (Round to the nearest whole %)
please answer i) and ii)
15. Given the following data, plot the stress-strain curve for this tensile steel specimen. The gage length of the specimen is 2.0". The cross sectional area is 0.195 in². Use the diagram that you plot to determine: a.) The Modulus of Elasticity b.) The Yield Stress c.) The Ultimate Stress LOAD P (pounds) Deformation (inches) 0.0000 3000 0.0007 0.0017 0.0025 6000 9000 12000 14000 0.0036 0.0044 15000 0.0060 0.0100 16000 17000 0.0250 0.2000 0.4000 18000 12000* rupture occurred. 2.
39)A tensile test specimen has a gage length=3.0 inches and a diameter= .75 inches. Yielding occurs at a load of 38000lbs. The corresponding gage length=3.0103 inches (neglect the .0.2% yield point). The maximum load of 54000lbs is reached at a gage length =3.453 inches. If fracture occurs at a gage length of 3.873inches, determine the percent elongation at fracture (Round to the nearest whole %)
Stress A Strain A Young's Modulus Yield Strength Ultimate Tensile Strength Rupture Strength
The following data are obtained from a tensile test of a copper specimen. - The load at the yield point is 148 kN. - Length of the specimen is 26 mm. - The yield strength is 83 kN/mm². - The percentage of elongation is 49 %. Determine the following (i) Diameter of the specimen, ii) Final length of the specimen, iii) Stress under an elastic load of 13 kN, iv) Young's Modulus if the elongation is 2.9 mm at 13 kN and (v) Final diameter if the percentage of reduction in area is 22 %. Young's Modulus of the Specimen (in N/mm?) Final Area of the Specimen at Fracture (in mm) 1. Final Diameter of the Specimen after Fracture (in mm)
The results of a tensile test are: Diameter of the specimen Gauge length Load at limit of Proportionality Extension at the limit of Proportionality Maximum Load : 10mm :40 mm :80kN : 0.06mm. :100 kN Calculate ultimate tensile stress and young's modulus.
I have this data about a experiment and the graph is given below Original diameter of specimen is 5mm final diamter is 2.5mm length initial is 27mm lf is unkown but %elongation is 28% The magnification is 16 to 1 each box is 1 cm the values from 1 to 5.8 kN(which is the limit of proportionality) for machines graph in cm is 0.25cm,0.5cm,0.9cm,1.2cm,1.6cm,1.9cm the values from 1 to 5.8 kN(which is the limit of proportionality) for machine+specimen graph in cm is 0.6cm,1cm,1.5cm,2cm,2.5cm,2.9cm Find the youngs modulus of the specimen
5.3) A cold-worked carbon steel was tested in a tensile test and the results are shown in Table 1 below: Table 1. Tensile test results Original diameter 10,00 mm Final diameter 7,60 mm Original gauge length 102,00 mm Final gauge length 114,30 mm Load at upper yield 31,21 kN Maximum force 36,25 kN Load at fracture 28,65 kN Factor of safety 2 For Questions 5.3.1 to 5.3.8, calculate the following tensile test properties based on the information provided in Table 1 above: 5.3.1) Stress at upper yield. ANSWER TO QUESTION 5.3.1 5.3.2) Ultimate tensile stress. ANSWER TO QUESTION 5.3.2
The following data are obtained from a tensile test of a copper specimen. - The load at the yield point is 152 kN. - Length of the specimen is 20 mm. - The yield strength is 86 kN/mm2. - The percentage of elongation is 48 %. Determine the following (i) Diameter of the specimen, ii) Final length of the specimen, iii) Stress under an elastic load of 10 kN, iv) Young's Modulus if the elongation is 2.2 mm at 10 kN and (v) Final diameter if the percentage of reduction in area is 28 %. Solution Initial Cross-sectional Area (in mm2) Answer for part 1 The Diameter of the Specimen (in mm) Answer for part 2 Final Length of the Specimen (in mm) Answer for part 3 Stress at the elastic load (in N/mm2) Answer for part 4 Young's Modulus of the Specimen (in N/mm2) Answer for part 5 Final Area of the Specimen at Fracture (in mm) Answer for part 6 Final Diameter of the Specimen after Fracture (in mm) Answer for part 7