EXERCISE 2.53 Collar C is pushed along the guide bar defined by y= 2(1-0.25x²), where x and y have units of meters. The angular speed of arm AB that actuates the motion is the constant value = 20 rad/s, so = ct. Determine the forces exerted on the collar by arm AB and the guide bar at x = 1 m. The mass of the collar is 2 kg, and gravitational effects are ignorable. (Hint: use Cartesian and polar coordinates to solve the problem.)

1. Kinetic energy due to rotation of the body is defined as a. (1/2) m (v.)² b. (1/2) m (v.)² + (1/2) I ² c. (1/2) La co² d. I, 00²

A box is moving in the i direction with a constant acceleration. A mass, suspended from the top of the box by a linear spring (unstretched length of zero), is moving to the right as well and isn't moving with respect to the box (the spring isn't changing in length and θ is constant). The force exerted by the spring on the mass is given by its spring constant k times its extension. For the present case, the spring is extended 5 cm from its rest length, k = 30 N/m and m = 0.15 kg. What is the angle θ equal to, and what is the acceleration of the box? You can solve for this without using the computer

find the center of mass, the velocity of the center of mass, the momentum, and the kinetic energy of the following system: m₁ = 1 kg T₁=1+2+3 k v₁ = 2î + 3ĵ m₂ = 1 kg T₂ = î -Ĵ+ k v₂ = 2ĵ + 3k