find the center of mass, the velocity of the center of mass, the momentum, and the kinetic energy of the following system: m₁ = 1 kg T₁= i + 2) + 3 k v₁ = 2î + 3ĵ m₂ = 1 kg T₂ = 1-j+ k v₂ = 2ĵ+ 3k

The figure shown below is released from rest with the spring unstretched. Use the datum shown for zero gravitational potential energy. For the values given below answer the following questions:Position 1 is Ha1 μk=0.14 k=32.5 Nm hA1=0.6 m mA=4.6 kg mB=1.3 kg What is the Gravitational Potential Energy for mass mA at position 1 (remember your signs)? What is the Gravitational Potential at position 1 for mB? What is the Potential Energy of the spring at position 1? What is the Kinetic Energy at position 1 for mA? What is the Kinetic Energy at position 1 for mB? Again we have the figure shown below that was released from rest with the spring unstretched. Use the datum shown for zero gravitational potential energy. At position 2 the spring is at its max stretch. Remember we have the values below; answer the following questions: μk=0.14 k=32.5 Nm hA1=0.6 m mA=4.6 kg mB=1.3 kg What is the max stretch in the spring?

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Q- A block of mass 100 kg is attached to springs of spring constant K₁ = 40 N/m and K₂ = 60 N/m. The block is displaced to the left through a distance of 2.5 m. The speed of the block when it passes through it's original position is _m/sec.