Exercise 1: Find the deflection at the point load and the slopes at the ends for the steel shaft which is simply supported at the bearing A and B as shown in Fig.1. Calculate the following: a. Deflection at the point load b. Slope at the ends 4- 1.25 x 10 mm 3000 N I4x 10 mm IXB 150 mm 75 mm 125 mm Fig-)

Structural Analysis
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Chapter2: Loads On Structures
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Exercise 1 :
Find the deflection at the point load and the slopes at the ends for the steel shaft which
is simply supported at the bearing A and B as shown in Fig.1.
Calculate the following:
a. Deflection at the point load
b. Slope at the ends
- 1.25 x 10 mm
3000 N
I2= 4x 10 mm
B
150 mm
75 mm
/-
125 mm
Fig-()
Take E-200 GPa.
Given:
Young's modulus, E = 200 GPa
- 200 x 10 Pa (or) 200 x 10 N/m2
E - 200 x 10 N/m2
= 2x 10 N/mm2
Moment of inertin,
Element i and 2, I, = 1.25 x 105 mm4
Element 3, 1, - 4 x 10 mm
3000 N
my. :
m2, 2
dyn. Fiy
150 mm
da Fay
d,3 Fay
dye, Fay
125 mm
t75 mm
Fig. (i).
For ciement 1, length L, = 150 mm
For element 2, length L, - 75 mm
For element 3, length L, = 125 mm
Point load at node 2, F, =' 3000 N
Fig.1
Transcribed Image Text:Exercise 1 : Find the deflection at the point load and the slopes at the ends for the steel shaft which is simply supported at the bearing A and B as shown in Fig.1. Calculate the following: a. Deflection at the point load b. Slope at the ends - 1.25 x 10 mm 3000 N I2= 4x 10 mm B 150 mm 75 mm /- 125 mm Fig-() Take E-200 GPa. Given: Young's modulus, E = 200 GPa - 200 x 10 Pa (or) 200 x 10 N/m2 E - 200 x 10 N/m2 = 2x 10 N/mm2 Moment of inertin, Element i and 2, I, = 1.25 x 105 mm4 Element 3, 1, - 4 x 10 mm 3000 N my. : m2, 2 dyn. Fiy 150 mm da Fay d,3 Fay dye, Fay 125 mm t75 mm Fig. (i). For ciement 1, length L, = 150 mm For element 2, length L, - 75 mm For element 3, length L, = 125 mm Point load at node 2, F, =' 3000 N Fig.1
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