Example 2-8. The space time required to achieve 80% conversion in a CSTR is 5 h. The entering volumetric flow rate and concentration of reactant A are 1 dm/min and 2.5 molar. respectively. If possible. deter- mine (1) the rate of reaction. -r = (2) the reactor volume. V = _ (3) the exit concentration of A. C₁ = space time for 80% conversion. . and (4) the PFR

Introduction to Chemical Engineering Thermodynamics
8th Edition
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Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
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(e) The space time required to achieve 80% conversion in a CSTR is 5h. The entering volumetric flow rate and concentration of reactant A are 1 dmVmin and 2.5 molar, respectively. If possible, determine (1) the rate of reaction, -rA=? (2) the reactor volume, V=? (3) the exit concentration of A, CA=? and (4) the PFR space time for 80% conversion.

P2-4 (a) Revisit Examples 2-1 through 2-3. How would your answers change if
the flow rate. FAG- were cut in half? If it were doubled?
(b) Example 2-5. How would your answers change if the two CSTRS (one
0.82 m³ and the other 3.2 m) were placed in parallel with the flow. Fo
divided equally to each reactor.
(c) Example 2-6. How would your answer change if the PFRs were placed
in parallel with the flow, FA, divided equally to each reactor?
(d) Example 2-7. (1) What would be the reactor volumes if the two interme-
diate conversions were changed to 20% and 50%, respectively. (2) What
would be the conversions, X, X₁, and X. if all the reactors had the same
volume of 100 dm³ and were placed in the same order? (3) What is the
worst possible way to arrange the two CSTRS and one PFR?
(e) Example 2-8. The space time required to achieve 80% conversion in a
CSTR is 5 h. The entering volumetric flow rate and concentration of
reactant A are 1 dm³/min and 2.5 molar. respectively. If possible. deter-
mine (1) the rate of reaction. -A = (2) the reactor volume. V =
and (4) the PFR
(3) the exit concentration of A. C₁ =
space time for 80% conversion.
Transcribed Image Text:P2-4 (a) Revisit Examples 2-1 through 2-3. How would your answers change if the flow rate. FAG- were cut in half? If it were doubled? (b) Example 2-5. How would your answers change if the two CSTRS (one 0.82 m³ and the other 3.2 m) were placed in parallel with the flow. Fo divided equally to each reactor. (c) Example 2-6. How would your answer change if the PFRs were placed in parallel with the flow, FA, divided equally to each reactor? (d) Example 2-7. (1) What would be the reactor volumes if the two interme- diate conversions were changed to 20% and 50%, respectively. (2) What would be the conversions, X, X₁, and X. if all the reactors had the same volume of 100 dm³ and were placed in the same order? (3) What is the worst possible way to arrange the two CSTRS and one PFR? (e) Example 2-8. The space time required to achieve 80% conversion in a CSTR is 5 h. The entering volumetric flow rate and concentration of reactant A are 1 dm³/min and 2.5 molar. respectively. If possible. deter- mine (1) the rate of reaction. -A = (2) the reactor volume. V = and (4) the PFR (3) the exit concentration of A. C₁ = space time for 80% conversion.
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