Answered: Example 1, given the two below…

Example 1, given the two below displacements, fined the magnitude of the displacement 2D – E D = (6.00i + 3.00j - 1.00k ) m and E = (4.00î – 5.00j + 800k) m %3D %3D

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter2: Fundamentals

Section: Chapter Questions

Problem 2.1MCQ: The rms value of v(t)=Vmaxcos(t+) is given by a. Vmax b. Vmax/2 c. 2Vmax d. 2Vmax

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Concept explainers

Dielectric Breakdown

A dielectric is a material with low electrical conductivity and so is classified as an insulator. Dielectric materials are used to block the flow of electricity through them, allowing them to behave as an insulators. They can also be used to store electric charge or improve capacitance.Dielectrics have no free electrons for conduction because electrons are tightly bound to the nucleus. Because dielectrics contain a small number of electrons for electrical conductivity, they have a dipole. The two primary roles of dielectrics in electrical devices are insulation and electrical energy storage. An electric field polarizes the dielectric, and the polarization of the molecules allows dielectric materials to store charge.

Question

Example 1, given the two below displacements, fined the magnitude of the displacement 2D – E
D = (6.00î + 3.00j – 1.00k) m and
Ë = (4.00i – 5.00j + 8.00k) m
%3D
%3D

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