Determine the rms current in the figure for Vrms = 16 V and C = 74µF
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- The peak distance of a sinusoidal waveform displayed on a C.R.O. screen is 6 cm and the 'volts/cm' switch is on 33 V/cm. The peak to peak voltage is given by O 396.00 V O 5.50 V O 139.99 V O 99.00 VFor the following parts, identify the name of each circuit, plot the output waveform, and find the DC output average voltage. Part (a) V 1 cycle V₁ = V sin cor Part (b) PE Part (c) Vm Vi ele eeeeeeeeeeeeee D D₂ D₁ D₂ R Va + D₂ D₁Ratio of dc output voltage to rms voltage is a. 0.318 b. 0.637 c. 0.45 d. 0.9
- Shown in the figure below is an "RL" circuit drive by an AC power source. The AC power source has an RMS voltage of Vps (RMS) = 9.84 Volts and is running at a frequency of f = 8.585e+04 Hz. The resistor has a resistance of R = 2170 and the inductor has an inductance of L = 3.54e-03 Henries. Vps R ww Write the FORMULA for the total impedance of the circuit Ztot = Determine the numerical value of Ztot = 2890.5 Determine the numerical value of $z= = 41 Determine the current through the circuit: • I(PEAK) = 4.81E-3 • I(RMS) = 3.404E-3 Determine the voltage across the resistor: • VR(PEAK) = 7.387 • VR(RMS) = 5.22 ✔✔ Amps ✔Amps Write the FORMULA for the phase of the total impedance of the circuit z... = | tan-1 2701 R x Volts X Volts Determine the voltage across the inductor: • VL(PEAK) = 9.184 • VL(RMS) = 6.49 ✔ Volts Volts L R²+ WL- ✔ degrees 2 If a second circuit were connected in parallel with the inductor, this circuit would be considered as: O a low-pass filter O a capacitive switcher…What is the frequency (in Hz) of the figure below? 250 usQ4: For Figure below for sinusoidal input waveform Display and sketch the input and the output waveforms: CH1 1kO CH2 D. Vout 20V p 1N4007 f=1 kHz GND
- The sinusoidal voltage trace displayed by the CRO, the time/cm switch is on 50 µs/cm and the volt/cm switch is on 20 V/cm. The width of one complete cycle is 3.6 cm and the peak to peak height is 5.8 cm. Determine the following: The frequency is = The peak to peak voltage is = The amplitude is = The R.M.S voltage is =5. Figure Q5 shows a parallel dipper circuit. Sketch the output waveform t, for one complete cycle. R Vi 10 V Si Si vo -10 V 7.3 V 5.3 V Figure Q5Vs(rms)=3.5 VL(rms)=4 Vc(rms)=0.8 VR(rms)=0.55
- The maximum value of sinusoidal voltage is given by Vm= 1 V, What is the value of Peak to Peak voltage?A pure sinusoidal current is being rectified. For the given maximum value of half wave rectified current is 50 A, then the rms value of full wave rectification will be 50 (a) A (b) 100 - A TC (c) 100 A (d)70.7 AIn an experiment, the function generator is adjusted to generate a square voltage at a certain frequency. This voltage is displayed on an oscilloscope and the reading is 16 V peak-to-peak. The rms value of this voltage is .What will be the rms value of this voltage if the frequency is doubled? Select one: O 16 Vrms 32 Vrms O 8 Vrms . 8 Vrms ..... O 5.657 Vrms 5.657 Vrms ....... O 8 Vrms . 16 Vrms O 16 Vrms 8 Vrms ......