Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN: 9780133594140
Author: James Kurose, Keith Ross
Publisher: PEARSON
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- ASAP Solution needed / Solution You're given a string of words. You need to find the word "Nemo", and return a string like this: "I found Nemo at [the order of the word you find Nemo]!" If you can't find Nemo, return "I can't find Nemo :(". Examples findNemo ("I am finding Nemo !") → "I found Nemo at 4!" wwwwwwww ➡ "I found Nemo at 1!" findNemo ("Nemo is me") www findNemo ("I Nemo am") wwwwwwwww "I found Nemo at 2!" (Ctrl)arrow_forwardlength(A)= ?arrow_forwardASAP Solution needed / Solution You're given a string of words. You need to find the word "Nemo", and return a string like this: "I found Nemo at [the order of the word you find Nemo]!" If you can't find Nemo, return "I can't find Nemo :(". Examples findNemo ("I am finding Nemo !") → "I found Nemo at 4!" wwwwwwwww findNemo ("Nemo is me") ➡ "I found Nemo at 1!" findNemo ("I Nemo am") ➡ "I found Nemo at 2!" wwwwwwww (Ctrl)arrow_forward
- ] ] is_bipartite In the cell below, you are to write a function "is_bipartite (graph)" that takes in a graph as its input, and then determines whether or not the graph is bipartite. In other words, it returns True if it is, and False if it is not. After compiling the above cell, you should be able to compile the following cell and obtain the desired outputs. print (is_bipartite({"A" : ["B", "C"], "B" : ["A"], "C" : ["A"]}), is_bipartite({"A" : ["B", "C"], "B" : ["A", "C"], "C" : ["A", "B"]})) This should return True False Python Pythonarrow_forwardWhat is the output of the following code?lst = [1, 2, 3, 4, 5, 6] for i in range(1, 6):lst[i] = lst[i - 1]print(lst)arrow_forwardComputer Engineering Labarrow_forward
- ] ] get_nhbr In the cell below, you are to write a function called "get_nhbr(Ist, graph)" that takes in two inputs: a list of vertices and a graph. The function is to return a list that contains the neighborhood of the vertices in 'Ist' (remember that this means you are finding the union of the individual vertices' neighborhoods). + Code + Markdown After compiling the above cell, you should be able to compile the following cell and obtain the desired outputs. print (get_nhbr(["A", "D"], {"A" : ["B"], "B" : ["A", "D", "E"], "C" : ["E"], "D":["B"], "E":["B","C","F"], "F":["E"]}), get_nhbr(["B", "C", "F"], {"A" : ["B"], "B" : ["A", "D", "E"], "C" : ["E"], "D":["B"], "E":["B","C","F"], "F":["E"]})) This should return ["B"] ["A", "D", "E"] Python Pythonarrow_forwardWhat does the following code do? In [1]: def mystery (a, b) : if b == 1: return a else: return a + mystery (a, b - 1) In [2]: mystery (2, 10) Out [2]: ?????arrow_forward
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