Scientists want to place a 3 x 10³ kg satellite in orbit around Mars. They plan to have the satellite orbit a distance equal to 1.8 times the radius of Mars above the surface of the planet. Here is some information that will help solve this problem: mmars = 6.4191 x 1023 kg mars = 3.397 x 105 m G = 6.67428 x 10-11 N-m²/kg² 1) What is the force of attraction between Mars and the satellite? N Submit 2) What speed should the satellite have to be in a perfectly circular orbit? m/s Submit 3) How much time does it take the satellite to complete one revolution? hrs Submit (+

Scientists want to place a 4 × 103 kg satellite in orbit around Mars. They plan to have the satellite orbit at a speed of 2330 m/s in a perfectly circular orbit. Here is some information that may help solve this problem: mmars = 6.4191 x 1023 kgrmars = 3.397 x 106 mG = 6.67428 x 10-11 N-m2/kg2 1.)What should the speed of the orbit be, if we want the satellite to take 8 times longer to complete one full revolution of its orbit?

a) Observations and trigonometry can be used to determine that Earth's moon has an orbital period of 27.32 days and a mean orbital radius of 384,400 km. Using this information, calculate the mass of the Earth. 2 M = 47² ² 2 C M= 4+1 (30214100000) 667 e

Scientists want to place a 4 × 103 kg satellite in orbit around Mars. They plan to have the satellite orbit at a speed of 2330 m/s in a perfectly circular orbit. Here is some information that may help solve this problem: mmars = 6.4191 x 1023 kgrmars = 3.397 x 106 mG = 6.67428 x 10-11 N-m2/kg2 1.)Which of the following quantities would change the radius the satellite needs to orbit at? a.)the mass of the satellite b.)the mass of the planet c.)the speed of the satellite   2.)What should the speed of the orbit be, if we want the satellite to take 8 times longer to complete one full revolution of its orbit?

29. Consider Planet X whose mass and radius are 9.05 x 1025 [kg] and 5.95 x 104 [m], respectively. If the weight of the object on the surface of the Earth is 2940 [N], what is its weight at height 750 [m] from the surface of the Planet X? Note: The gravitational constant is G = : 6.6743 x 10-11 m3 A. 3.70 × 108 [N] C. 4.99 x 108 [N] B. 4.88 x 108 [N] D. 5.12 x 108 [N] Lkg

A new planet named Vulcan has been discovered. Vulcan is a rather large planet with a radius twice that of Earth and a mass three times that of Earth. An astronaut has a mass of 60.0 kg and weighs about 132 lbs. on Earth. If the astronaut is on the planet Vulcan, what is her weight? The following numerical values may be helpful in this question. G = 6.67 ∙10-11 N∙m2/ kg2 Earth’s mass = 5.98 · 1024 kilograms g = 9.80 m/sec2 1 kilometer = 1000 meters

The gravitational acceleration constant gx on Planet X can be approximated by determining the acceleration of an object assuming Newton's Law of Universal Gravitation. If gx = 3.8 m/s^2 , G = 6.7 x 10^-11 Nm^2/kg^2, and Planet X's radius is 4000 km, what is the approximate mass of planet X? Give answer in kg.

1. The distance between Jupiter and Mars (r) is 3.84 x 10° m. What is the magnitude of gravitational force each exerts on the other? x Jupiter's mass = 1.898 x 10^27 kg X Mars's mass = 6.39 × 10^23 kg x r= 3.84 x 108 m X G= 6.67x 10-11 N m² / kg? 2. The distance between a 750-g person and a 300-g person is 12000km. What is the magnitude of the gravitational force each exerts on the other. Universal constant = 6.67 x 10-11 N m² / kg² 3. The distance between a 7500-kg earth’s debris and a 1.898 × 10^27 kg space debris is 120m. What is the magnitude of the gravitational force each exerts on the other. Universal constant = 6.67 x 10-11 N m² / kg? 16

A newly discovered planet X has a mass of 36.7 × 1023 kg and radius 2.47 × 106 m.  What is g on this planet's surface, in m/s2?

Two lead spheres are separated by 0.207 m, centre-to-centre. One sphere has a mass of 5.53 kg. The gravitational attraction between the spheres is 6.06x108N. What is the mass of the other sphere? Express your result in SI units but don't include the units in your answer.