Engineering Mechanics: Dynamics 7th Edition James L. Meriam, L. G. Kraige, J. N. Bolton
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- Physical Properties: https://education.wiley.com/player/index.html#/res;url=https:%2F%2Feducation.wiley.com%2Fcontent%2FBergman_Fund_Heat_Mass_8e%2Febook%2Fepub%2F9781119353881%2FOPS%2Fa01.xhtml%23headda01 Mathematical Functions: https://education.wiley.com/player/index.html#/res;url=https:%2F%2Feducation.wiley.com%2Fcontent%2FBergman_Fund_Heat_Mass_8e%2Febook%2Fepub%2F9781119353881%2FOPS%2Fa02.xhtml%23headda01The Laws of Physics are written for a Lagrangian system, a well-defined system which we follow around – we will refer to this as a control system (CSys). For our engineering problems we are more interested in an Eulerian system where we have a fixed control volume, CV, (like a pipe or a room) and matter can flow into or out of the CV. We previously derived the material or substantial derivative which is the differential transformation for properties which are functions of x,y,z, t. We now introduce the Reynold’s Transport Theorem (RTT) which gives the transformation for a macroscopic finite size CV. At any instant in time the material inside a control volume can be identified as a control System and we could then follow this System as it leaves the control volume and flows along streamlines by a Lagrangian analysis. RTT:DBsys/Dt = ∂/∂t ʃCV (ρb dVol) + ʃCS ρbV•n dA; uses the RTT to apply the laws for conservation of mass, momentum (Newton's Law), and energy (1st Law of…Define dimensional homogeneity.
- Dynamics of Rigid Bodies Problem: 1.) A diver jumps from a height of 3.0 metres above the height of the water and touches the surface 1.0 s later. What was his velocity when he hit the water? 2.) A motorcyclist, travelling at a speed of 30 m/s, sees an obstacle 100 metres in front of him and puts on the brakes. He hits it 5.0 seconds later. If the motorcycle slows down uniformly, how fast was it going at the instant of the collision?3. The relationship between arterial blood flow and blood pressure in a single artery satisfies the following first-order differential equation: dP(t) + dt RC mmHg (cm³/s) P(t) = where Qin is the volumetric blood flow, R is the peripheral resistance, and C is arterial compliance (all constant). Qin-60 cm³/s and the initial arterial pressure is 6 mmHg. Also, assume R = 4 and C= 0.4- Oin cm³ mmHg (a) Find the transient solution Ptran(t) for the arterial pressure. The unit for P(t) is mmHg. (b) Determine the steady-state solution Pss(t) for the arterial pressure. (c) Determine the total solution P(t) assuming that the initial arterial pressure is 0.Heat is being generated in a fuel element at a volumetric heat generation rate of q′′′ = 1300 kW/m3. The fuel element is a rectangular parallelepiped of thickness 2 cm with a height of 2 m and width of 1 m. The fuel thermal conductivity is k = 3.5 W/m·C. Find the rate of heat transfer from the fuel element at steady state condition. [Ans.: 52 kW].
- List and describe the three necessary conditions for complete similarity between a model and a prototype.3. One model of the glomerular membrane is a microporous membrane in which right cylindrical porespenetrate all the way through the membrane. Assume that the pores have a length of 50 nm and aradius of 3.5 nm. The viscosity of plasma is 0.002 Pa s. The average hydrostatic pressure in theglomerulus is 60 mm Hg, hydrostatic pressure in Bowman’s space is 20 mm Hg and the averageoncotic pressure of glomerular capillary blood is 28 mm Hg.A. Calculate the flow through a single pore assuming laminar flow (use the Poiseuille flowequation).B. How many pores would there have to be to produce a normal GFR?C. If the total aggregate area of the kidneys for filtration is 1.5 m2, what is the density of thepores (number of pores per unit area)D. What fraction of the area is present as pores1. The general form of linear second-order differential equation can be written in the form: و بار / كلية الهندسة Q4)/ grap dy q(x)y = r(x) d'y +p(x) dx dy b. dx - F(x)y = F(x) x2 dy dx - xy = C. d. r2 d?y dx2 -f(x)y = F(x) 2431)(5-1) 3 (3-21)2 a. (221 -91i) / 169 b. (21 + 52i)/ 13 c. (-90+220i)/169 d. (-7+17i)/ 13 2. Simplify: الحدار المك المراغة 3. If the roots of second order differential equation is complex conjugate, then the gene contain: a. sinusoidal functions and exponentials b. constant and two exponentials c. two constants and two exponentials d. two constants and one exponential 5 4. The order and degree of the differential: 3(3 - + 4y = sinx* are: d²y a. First-order, First-degree- b. First-order, second-degree Second -order, First -degree d. Second -order, second-degree dx2 lo - 2i tisi. 8- 12i 5. The particular solution of (D² + 4)y = cos 2x is equal to: a. sin 2x b. cos 2x 13+159 C. 4 cos 2x d. 4 sin 2x 5-12 lo Best wishes الامتحانية د. مازن ياسین عبود رئيس القسم بن فاضل…
- Engineering mechanics static1. A spring mass system serving as a shock absorber under a car's suspension, supports the M 1000 kg mass of the car. For this shock absorber, k = 1 × 10°N /m and c = 2 × 10° N s/m. The car drives over a corrugated road with force %3| F = 2× 10° sin(@t) N . Use your notes to model the second order differential equation suited to this application. Simplify the equation with the coefficient of x'" as one. Solve x (the general solution) in terms of w using the complimentary and particular solution method. In determining the coefficients of your particular solution, it will be required that you assume w – 1z w or 1 – o z -w. Do not use Matlab as its solution will not be identifiable in the solution entry. Do not determine the value of w. You must indicate in your solution: 1. The simplified differential equation in terms of the displacement x you will be solving 2. The m equation and complimentary solution xe 3. The choice for the particular solution and the actual particular solution x,…a) A composite of ceramic and polymer will have a higher elastic modulus than either of the individual components b)Maximum tensile strength of polymers is usually lower than metals c)The ductility of ceramics and polymers is much better than metals d)The elastic modulus of ceramics and metals is usually larger than polymers