en truss, find the force of m = 60 kN olve this using two methods: (a) Metho
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- Pipe 2 has been inserted snugly into Pipe I. but the holes Tor a connecting pin do not line up; there is a gap s. The user decides to apply either force P:lo Pipe I or force P-, to Pipe 2, whichever is smaller. Determine the following using the numerical properties in the box. (a) If only P{is applied, find Pt{tips} required to close gap s; if a pin is then inserted and Ptremoved, what are reaction forces RAand RBfor this load case? (b) If only P2is applied, find P2{kips) required to close gap a; if a pin is inserted and P2removed, what are reaction forces R^ and RBfor this load case? (c) What is the maximum shear stress in the pipes, for the loads in parts (a) and (b)? (d) If a temperature increase IT is to be applied to the entire structure to close gaps{instead of applying forces Ptand P2), find the AT required to close the gap. If a pin is inserted after the gaphas closed, what are reaction forces .''.', and RBfor this case? (e) Finally, if the structure (with pin inserted) then cools to the original ambient temperature, what are reaction forces Rtand PFrom the given truss, find the force of member GH, Load 1 = 30 kN, Load 2 = 60 kN Solve this using two methods: (a) Method of Joints or (b) Method of Sections. A 112.5 5 m B 4 m H Load 1 5 m G Load 2 5 m F Load 1 5 m 4 GRAY B F F₁ ROY
- RAY F Enter Fpc: Enter Fr The figure above is a pin-joint frame with horizontal member length 1 = 2m and vertical member length h = 4m. (Note that the diagram is not to scale.) You are given that F₁ =45kN, RAY = 15kN and Rpy = 30kN. Use the method of sections to calculate the forces in members BC, FC and FE. Enter your answers in kilonewtons (kN) correct to 2 decimal places. Enter Fac: KN KN F₁ KN RDYThe figures below show a formed sheet-steel bracket. The total distributed load “W” on the bracket is 20 kN. It is secured to the support with two grade 5.8 bolts. The joint constant is C=0.183, and the bolts are preloaded to 70 percent of the proof load. The dimensions of the top flange are the same as the mounting flange.a) Find the external loads (P1 and P2) carried by upper and bottom bolts respectively if both resist the moment?b) Find the upper bolt diameter by ignoring direct shear load and determine/select a standard metric bolt size with a pitch for a design factor of 1,4.c) Is there any need to enlarge 5 mm dia. holes in the bracket?Problem: Use method of joints (MOJ) and/or method of sections (MOS). Calculate the member force of EB. 4 m A 4 m E B 5 m F C 10 kN D 4 m
- BAPS JUM uestion 1 Using the method of joints, find forces in each member of the truss shown in the figure below. 3 m D 60° 30° 3 m 60 30 A 500 kN50 KN A 250 KN 100 KN B с Reaction of AH (RAH)= Reaction of Av (RAV)= Reaction of H (RH)= Force at CE (FCE)= 200 kN E 4 panels @ 6 m each Problem 2: Each member has an area of 1150 mm2 Solve for the TRUSS REACTIONS of Problem 2 and FORCE of member CE. KN KN kN kN 100 KN F G 50 KN H 250 KN 6 m • Do not include UNITS and answer in 3 DECIMAL DIGITS (ex. 0.000, 12.000, 130.123, 4.125, 0.500 ) • Do not include nature of forces (if C or T, or +/-)In the truss loaded and supported as shown, compute the following using the Method of Joints: (a) JK = (b) KD = (c) DE = 300 lb 300 lb 800, lb 300, lb 800, lb 9 ft в C D E 700 b. 700 lb 6 panels e 5 rt/paret
- From the given truss, find the force of member AH, Load 1 = 178 kN, Load 2 = 399 KN Solve this using two methods: (a) Method of Joints or (b) Method of Sections. A 5 m B 4 m H Load 1 5 m C G Load 2 5 m SVERIGE. D F Load 1 5 m EAgui - 4550/2 =2276 two plates each with thickness t - 16 mm are bolted together with 6-222 mndia. bolts firming alap Joint Bolt spacing are follows St- $40mm S2 - 80mm, S3=150mm effective bolt hole dia. is 25mm A36 is used. Compute the allowable tensile Strength P t = 16 mm &t 52 747₁ 0 O O 40 60 80 40 +=16mm S-400 $3-100 S2-40 7 @ 4umm Ptouch &O O166% 00:27 MENG250 - Practice Assign... Problem 2-15 Determine the design angle ø (0° < ø< 90°) between struts AB and AC so that the 400-lb horizontal force has a component of 500 lb directed from A towards C. What is the component of force acting along member AB? Take 0 = 40°. 400 lb A te B