Elemental analysis of a compound with molar mass 342.3 g/mol gives the following mass percent composition: C 42.11%, H 6.48%, O 51.41%. Find the molecular formula of the compound. Enter your answer in the space below using the following format: if the molecular formula of a compound containing elements X, Y, and Z is X2YZ3 enter your answer as X2YZ3

Atoms A and B interact to form a compound, AB2. When measured, atom A has a partial negative charge and atom B has a partial positive charge. From this information, we can conclude what? Select only ONE answer choice. Note: - means "approximately equal to" , A > B means "A is greater than B" , and A B: AB2 is hydrophilic Not enough information to answer the question

what is the correct answer ง The two possible states of a substance in water, dissolved (D) and undissolved (U), are depicted in the PEC diagram below. What is true about this substance? Ep U D # configurations Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a It is soluble in water at all temperatures b It is insoluble in water at all temperatures C It is soluble in water only at high temperatures d It is soluble in water only at low temperatures

In 1895 a student prepared three coordination compounds of chromium with the same formula CrCl2(H2O). The table below gives the color of each compound along with the number of CI ions in solution per formula unit of the compound. Complete the table by filling in the modern formula for each compound. Metal chromium has a coordination number of 6 in these compounds and an oxidation state of +2. Compound (a) Color Bright blue (b) Light green (c) Yellow Part 1 of 3 Modern formula for (a): х G CI Ions in Solutions per Formula Unit 2 1 0 00 ola

Unshared, or lone, electron pairs play an important role in determining the chemical and physical properties of organic compounds. Thus, it is important to know which atoms carry unshared pairs. Use the structural formulas below to determine the number of unshared pairs at each designated atom. Be sure your answers are consistent with the formal charges on the formulas. H₂C H₂ b Hc N CH2 The number of unshared pairs at atom a is The number of unshared pairs at atom b is The number of unshared pairs at atom c is The number of unshared pairs at atom a is 1 v The number of unshared pairs at atom b is Ov The number of unshared pairs at atom c is 1.

A sample of helium is initially at 605 torr in a volume of 2.85 L. At 24.7 °C you found the density of He to be 0.130 g/L and the density of Ar to be 1.30 g/L even though both samples had the same number of moles. Which one of the following best explains why the densities are different? A B C D Argon is a heavier atom than helium, so it has more mass in the same volume occupied by the gas. Argon is a larger atom than helium so it occupies more volume. An argon atom is more dense than a helium atom. The densities are different only because of rounding.

The molecular weight of glucose is 180.16 g/mol. Say you want to make 100 ml of a 0.6M solution of glucose. How much glucose and water should you use? Show your calculations for how you would make this solution.

According to Aristotle’s density equation, if 4.686 grams of the sugar glucose (C6H12O6) occupies a volume of 3.0 cubic centimeters, then glucose must have a density of: 14.058 grams/cm3 7.686 grams/cm3 1.686 grams/cm3 1.562 grams/cm3 0.6402 grams/cm3