arth to a distant planet is 9 x 10^10 m. A 64 Mbps point-to-point link using a stop-and-wait protocol for frame transfer has what channel utilization? Assume 32 KB frame size and 3 × 10^8 m/s light speed.
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Earth to a distant planet is 9 x 10^10 m. A 64 Mbps point-to-point link using a stop-and-wait protocol for frame transfer has what channel utilization? Assume 32 KB frame size and 3 × 10^8 m/s light speed.
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- A planet located far from Earth is around 9 x 1010 meters away. If a stop-and-wait protocol is employed for frame transmission on a 64 Mbps point-to-point link, what is the channel utilization? Assume that the speed of light is 3 108 m/s and that the frame size is 32 KB.Suppose you are designing a sliding window protocol for a 1-Mbps point-to-point link to a stationary satellite revolving around the earth at 3 x 104 km altitude. Assuming that each frame carries 1 KB of data, what is the minimum number of bits you need for the sequence number in the following cases? Assume the speed of light is 3 x 108 m/s. (a) RWS=1 (b) RWS=SWSThe distance from earth to a distant planet is approximately 9 x 10^10 m. What is the channel utilization if a stop-and-wait protocol is used for frame transmission on a 64 Mbps point-to-point link? Assume that the frame size is 32 KB and the speed of light is 3 × 10^8 m/s.
- A distant planet is about 9 x 1010 metres from the surface of the Earth. What is the channel utilisation of a point-to-point connection that operates at 64 megabits per second and uses a stop-and-wait protocol for frame transmission? Let's say that the speed of light is 3 108 metres per second, and that the frame size is 32 kilobytes.Suppose that we are sending a 30 Mb MP3 file from a source host to a destination host. All links in the path between source and destination have a transmission rate of 10 Mbps. Assume that the propagation speed is 2 × 108 meters/sec, and the distance between source and destination is 10,000 km. 1. Now suppose there is only one link between source and destination, and there are 10 FDM channels in the link. The MP3 file is sent over one of the channels. What is the end-to-end delay?Suppose you are designing a sliding window protocol for a 2Mbps point to point link to the moon, which has a one way latency of 10 sec. Assume that, each frame carries 1KB of data, what is the minimum number of bits you need for the sequence number?
- Suppose a 128-Kbps point-to-point link is set up between Earth and a rover on Mars. The distance from Earth to Mars (when they are closest together) is approx- imately 55 Gm, and data travels over the link at the speed of light-3 × 108 m/s. (a) Calculate the minimum RTT for the link. (b) Calculate the delay x bandwidth product for the link. (c) A camera on the rover takes pictures of its surroundings and sends these to Earth. How quickly after a picture is taken can it reach Mission Control on Earth? Assume that each image is 5 Mb in size.Consider TDM-based circuit switching with 8000 frames per second and 32 time slots per frame. During each time slot 8 bits are sent. What is the shortest time possible (in seconds) to transmit a 1 Mbyte file over the given link?Consider a full-duplex 256 Kbps satellite link with a 240 millisecond end-to-end delay. The data frames carry a useful payload of size 12,000 bits. Assume that both ACK and data frames have 320 bits of header information, and that ACK frames carry no data. What is the effective data throughput When using Stop and Wait?
- What is the total delay (latency) for a frame of size 78 million bits that is being sent on a same link with 9 intermediate devices having a queuing time of 83 μs and a processing time of 93 μs? The length of the link is 2000 Km. The speed of carrier inside the link is 2.8 × 108 m/sTopic :- Data link Layer A channel has a bit rate of 4 kbps and a propaga tion delay of 20 msec. For what range of frame sizes does stop-and-wait given an efficiency of at least 50 percent? Note:- Final Answer L= 5.33× 10-7 kbps Give step by step answerSuppose a 128-kbps point-to-point link is set up between the Earth and a rover on Mars. The distance from the Earth to Mars (when they are closest together) is approximately 55 Gm, and data travels over the link at the speed of light-3 × 108 m/s. (a) Calculate the minimum RTT for the link. X (b) Calculate the delay x bandwidth product for the link. (c) A camera on the rover takes pictures of its surroundings and sends these to Earth. How quickly after a picture is taken can it reach Mission Control on Earth? Assume that each image is 5 Mb in size.