Earth is approximately a solid sphere, has a mass of 5.98×1024 kg, a radius of 6.38×106 m, completes one revolution about its central axis each day, and orbits the Sun once each year (the Earth–Sun distance is 1.50×1011 m). Calculate the rotational kinetic energy ?axis of Earth as it spins on its axis. ?axis=   JJ Calculate the rotational kinetic energy ?orbitKorbit of Earth as it orbits the Sun. ?orbit=Korbit=   J

A neutron star of mass 2 x 10 kg and radius 11.1 km rotates with a period of 0.02 seconds. What is its rotational kinetic energy? KE = × 1012 J rot Question Help: Message instructor Submit Question

The flywheel of a steam engine runs with a constant angular speed of 132 rev/min. When steam is shut off, the friction of the bearings and the air brings the wheel to rest in 2.5 h. What is the magnitude of the constant angular acceleration of the wheel in rev/min2? Do not enter the units. 8.80x10-1 You are correct. Your receipt no. is 161-6726 Previous Tries How many rotations does the wheel make before coming to rest? 9.90x103 You are correct. Your receipt no. is 161-5241 Previous Tries What is the magnitude of the tangential component of the linear acceleration of a particle that is located at a distance of 50 cm from the axis of rotation when the flywheel is turning at 66.0 rev/min? 6.14 10^-4 m/s^2 Submit Answer Incorrect. Tries 8/40 Previous Tries What is the magnitude of the net linear acceleration of the particle in the above question? Submit Answer Tries 0/40

2. We can use a simple model which uses our understanding of uniform circular motion to estimate the largest possible rotational speed of a planet around its own axis. For a planet of mass M and radius R our model assumes that the planet "falls apart" when the loose rocks on the surface at the equator are no longer sitting on the surface because they leave the surface. A loose rock of mass m is shown on the equator in the drawing. M m R С. Now return to the 'slowly' rotating planet (where the loose rocks are not flying off the surface) and consider a loose rock that is not on the equator, but at some higher latitude, 0 (as shown). Do you need forces besides gravity and the normal force to make this situation possible? Justify your answer (you just need to justify whether you need another force but not what that other force might be if it is needed).