Suppose you are standing within the rim of a circular space station, in outer space. The rim revolves around the center of the space station at a speed of 300 (m/s). If the radius of the station is 3,000 (m). 1) What is the tangential speed of the space station? 2) What is the rotational speed of the space station? Note: Use S.I. units

At it's peak, a tornado is 75m in diameter and carries 470m/s wind at its outer edge. What is it's angular speed in radians per second?

A rotating space station is said to create "artificial gravity"—a loosely-defined term used for an acceleration that would be crudely similar to gravity. The outer wall of the rotating space station would become a floor for the astronauts, and centripetal acceleration supplied by the floor would allow astronauts to exercise and maintain muscle and bone strength more naturally than in non-rotating space environments. If the space station is 210 m in diameter, what angular velocity would produce an "artificial gravity" of 9.80 m/s2 at the rim?  ________ rpm

After a nuclear apocalypse on Earth, humans have built a space station known as the Ark. It has multiple sections controlled by different political factions, but one thing they all have in common is the need for artificial gravity. This is done in each section by setting a piece of the Ark spinning around the central axis of the station. The largest section of the station is a complete ring with a radius of 1000 m.a) What is the rotational velocity required to simulate gravity?b) One day on Earth is the defined by the amount of time it takes the Earth to rotate once around its axis and is 86,400 s. How many seconds is one “day” on this section of the station?c) When an inhabitant standing as they would on Earth, In which direction do their heads points? (which piece of the station)

How do I find the tangential speed of a ball going in uniform circular motion, in the problem I'm working on, a 1.3 m long string makes a 48.8 degree angle below the hoizontal. I am confused as to how I find the w to plug into the Vt=rw equation to get the tangential speed. Thanks for your help!

A rotating space station is said to create “artificial gravity”: A loosely-defined term used for an acceleration that would be crudely similar to gravity. The outer wall of the rotating space station would become a floor for the astronauts, and centripetal acceleration supplied by the floor would allow astronauts to exercise and maintain muscle and bone strength more naturally than in non-rotating space environments. If the space station is 180 meters in diameter, what angular velocity would produce an “artificial gravity” of 9.80 meters per second squared at the rim in radians per second?

Problem 12: A merry-go-round is a playground ride that consists of a large disk mounted to that it can freely rotate in a horizontal plane. The merry-go-round shown is initially at rest, has a radius R = 1.3 meters, and a mass M = 241 kg. A small boy of mass m = 46 kg runs tangentially to the merry-go-round at a speed of v = 1.8 m/s, and jumps on. Randomized Variables R = 1.3 meters M = 241 kg m = 46 kg v = 1.8 m/s

A key lime pie in a 8.50 in8.50 in diameter plate is placed upon a rotating tray. Then, the tray is rotated such that the rim of the pie plate moves through a distance of 233 in.233 in. Express the angular distance that the pie plate has moved through in revolutions, radians, and degrees. what is the angular distance in revelutions? what is the angular distance in radians? If the pie is cut into 1010 equal slices, express the angular size of one slice in radians, as a fraction of ?. what is the angular size =pi x in radians?

1. The horizontal circular platform weighs 500 lb and has a radius of gyration of kz = 8 ft from the z-axis passing through O. The platform is free to rotate about the z-axis and is initially at rest. A person having a weight of 150 lb begins to run along the edge in a circular path of radius 10 ft. If they maintain a speed of 4 ft/s relative to the platform, determine the angular velocity of the 10 ft platform. Neglect friction. I don't think we have dealt with relative velocity in this context, but it follows our earlier relative velocity treatment. Here all speeds are in the t-direction. vp is the speed of the person, and vp is the speed of the disk at the location of the person. Then vp = vp + Vp/D, same as before. You are given vpp = 4 ft/s.

Please don't provide handwritten solution ...