2. We can use a simple model which uses our understanding of uniform circular motion to estimate the largest possible rotational speed of a planet around its own axis. For a planet of mass M and radius R our model assumes that the planet "falls apart" when the loose rocks on the surface at the equator are no longer sitting on the surface because they leave the surface. A loose rock of mass m is shown on the equator in the drawing. M m. R Now return to the 'slowly' rotating planet (where the loose rocks are not flying off the surface) and consider a loose rock that is not on the equator, but at some higher latitude, 0 (as shown). Do you need forces besides gravity and the normal force to make this situation possible? Justify your answer (you just need to justify whether you need another force but not what that other force might be if it is needed). С. -------

PRINTER VERSION 1 BACK NEXT Chapter 13, Problem 025 Your answer is partially correct. Try again. A solid sphere of uniform density has a mass of 8.7 x 104 kg and a radius of 1.2 m. What is the magnitude of the gravitational force due to the sphere on a particle of mass 6.5 kg located at a distance of (a) 4.2 m and (b) 0.34 m from the center of the sphere? (c) Write a general expression for the magnitude of the gravitational force on the particle at a distance rs 1.2 m from the center of the sphere. (a) Number 2.139E-6 Units (b) Number 2.36E-6 Units (c) |Fon m = k•r, where k = 2.184E-5 IN/m Click if you would like to Show Work for this question: Open Show Work

Geostationary satellites are used in television transmission. A geostationary satellite of mass 4.45 x 10 kg is used to transmit television programming to the TV on Earth. d. i. State the orbital period of the satellite. ii. Calculate the angular velocity of the satellite. iii. Calculate the distance between the center of mass of the Earth and the center of mass of the geostationary satellite.

q2

35- A solid sphere of mass m and radius r can rotate without slipping along the path shown in the figure. At the height h where the sphere will start its motion from rest, the lowest part of the sphere is higher than the lowest part of the circular part of the road with radius R (R = 5r). What should be the minimum height (h) of the point where the sphere will start to move in order for the sphere to fully circle this circular path?

3. The Earth has a mass of 5.97 X 10²4 kg, and the Moon has a mass of 7.36 × 102 kg. The Moon orbits the Earth at a distance of 384,000 km; that is, the center of the Moon is a distance of 384,000 km from the center of the Earth, as shown below. How far from the center of the Earth is the center of mass of the Earth-Moon system? Earth -5.97-104 kg 384,000 km -7.36 102 kg Moon

3. The Earth has a mass of 5.97 X 10²4 kg, and the Moon has a mass of 7.36 × 102 kg. The Moon orbits the Earth at a distance of 384,000 km; that is, the center of the Moon is a distance of 384,000 km from the center of the Earth, as shown below. How far from the center of the Earth is the center of mass of the Earth-Moon system? Earth -5.97-104 kg 384,000 km -7.36 102 kg Moon

PRINTER VERSION 4 ВАСК NEXT Chapter 13, Problem 079 A certain triple-star system consists of two stars, each of mass m = 4.8×1030 kg, revolving in the same circular orbit of radius r = 3.2x1011 m about a central star of mass M = 6.9x1033 kg (the figure). The two orbiting stars are always at opposite ends of a diameter of the orbit. Calculate the period of revolution of the stars. Number Units the tolerance is +/-2% Click if you would like to Show Work for this question: Open Show Work

Number 4 needs answered

Intro Physics I, Homework #7 See Walker Ch. 5, 6.1, 6.3, 7.1-7.2, 13.1 Submit to Google Classroom by 10 P.M., Monday, April 4 Remember to show all work and include units In Newton's late 17th century era, there were relatively accurate estimates, from terrestrial and astronomical observations and experiments, of the distance of the Earth to the Sun (dEs = 150 million 1. kilometers) and the circumference of the Earth (Cp = 40,000 kilometers [the meter was later defined during the late 18th century French revolution in relation to the size of the Earth]). Newton further estimated, likely based on the density of rocks, that the Earth was a solid sphere with a density about 6 times the density of water, which has density of pwater = 1 g/cm³.