A pinjointed fourbar linkage is shown in the figure below.The link lengths are L1 = 7.8 in., L2 = 2.9 in., L3 = 7.25 in. and L4= 3.5 in.Using the current position, 02-100°, the position analysis has determined that 04 = 214.25°.Currently, link 2 is traveling at 5.50 rad/s CCWLepB.Figure 6.7 Four-bar linkage acceleration analysisThe angular velocities of link 3 w3 and and link 4 Wa are:Select one:O a. w3 = 3.589 rad/s, Wa = -2.91 rad/sO b. w3 = 2.07rad/s, wa = -2.91 rad/sC. W3 = 2.7 rad/s, wa 3.428 rad/sO d. w3 = 2.07 rad/s, w4 = -3.38 rad/s

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e below. The link lengths are L1 = 7.8 in., L2 = 2.9 in., L3 = 7.25 in. and L4 = 3.5 in. Using the current position, 02 -100°, the position analysis has determined that 04= 214.25°. Currently, link 2 is traveling at 5.50 rad/s CCW

e below. The link lengths are L1 = 7.8 in., L2 = 2.9 in., L3 = 7.25 in. and L4 = 3.5 in. Using the current position, 02 -100°, the position analysis has determined that 04= 214.25°. Currently, link 2 is traveling at 5.50 rad/s CCW

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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theta O = 55 The link length and value of O2 for some four bar linkage are defined below, (drive link =4.2 cm , coupler link =5.9 cm , follower link = 5.9 cm, fixed link= 6.85 cm 1. draw the linkage to scale and graphically find all possible solution (both open and cross) for 03 and O4 2. If w = 2 rad /s (CCW) find the angular velocity for bar 3 and 4 3.if a= 5 rad/s? (Ccw) find the normal and tangential acceleration for link 3 and 4
A pinjointed fourbar linkage is shown in the figure below. The link lengths are L1 = 7.8 in., L2 = 2.9 in., L3 = 7.25 in. and La = 3.5 in. Using the current position, 02 110°, the position analysis has determined that 0 = 209.21°. Currently, link 2 is traveling at 10 rad/s CW B. 8, =0 Figure 6.7 Four-bar linkage acceleration analysis The angular velocities of link 3 wz and and link 4 wa are: Select one: O a. w3 = -4.29 rad/s, wa = 4.81 rad/s O b. w3 = 2.7 rad/s, w4 = 3.428 rad/s O c. W3 = -4.29 rad/s, wa = -4.38 rad/s O d. w3 = 3.589 rad/s, wa = 4.81 rad/s %3! %3D
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A pinjointed fourbar linkage is shown in the figure below. • The link lengths are L, = 7.8 in., L2 = 2.9 in., L3 = 7.25 in. and L4 = 3.5 in. Using the current position, 82 =110°, the position analysis has determined that 04 = 209.21°. Currently, link 2 is traveling at 10 rad/s CW Le B. O, =0 Figure 6.7 Four-har linkage acceleration analysis The angular velocities of link 3 w3 and and link 4 wa are: Select one: a. W3 = 3.589 rad/s, wa = 4.81 rad/s O b. w3 = -4.29 rad/s, w4 = -4.38 rad/s O c. W3 = -4.29 rad/s, wa = 4.81 rad/s d. w3 = 2.7 rad/s, wa- 3.428 rad/s
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